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MrMuchimi
2 years ago
11

Heyyyyy pleasse help me please please and thank you

Mathematics
1 answer:
dimulka [17.4K]2 years ago
7 0

Answer:

x ≈ 33.1°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = \frac{opposite}{adjacent} = \frac{125}{192} , then

x = tan^{-1} ( \frac{125}{192} ) ≈ 33.1° ( to the nearest tenth )

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Greater than because they are negative
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3 years ago
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Helpppp plz will give brainliest
garik1379 [7]
11x = 44
X=4
44 + 7 = 51


5x = 20
31 + 20 =51

51 = 51
6 0
2 years ago
Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81
Anton [14]
Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)

with partial derivatives (set equal to 0)

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}
L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}
L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}
L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81

Substituting the first three equations into the fourth allows us to solve for \lambda:

x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}

For each possible value of \lambda, we get two corresponding critical points at (\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3).

At these points, respectively, we get a maximum value of f(3\sqrt3,3\sqrt3,-3\sqrt3)=9\sqrt3 and a minimum value of f(-3\sqrt3,-3\sqrt3,3\sqrt3)=-9\sqrt3.
5 0
3 years ago
What is the equation of the line through 4.2 and 0, -2?
MissTica

Answer:

y = x-2

Step-by-step explanation:

y = mx + b as an equation

m = slope

slope = (change in y) / (change in x) = (y₂-y₁)/(x₂-x₁) = (y₁-y₂)/(x₁-x₂) = (2-(-2))/(4-0) = 4/4 = 1

y = 1*x + b

plug a value in, e.g. (0, -2)

-2 = 1 * 0 + b

-2 = b

our equation is thus

y = x - 2

7 0
2 years ago
Please Help. Tristen is building 3 trophies using Legos. He needs 324 total Legos. Tristen uses 220 Legos for the largest trophy
velikii [3]

Answer:

1. The equation is given as

324 = 220 +135 + C

2. We have 166 As the correct answer but is not in the option

Step-by-step explanation:

We are been given the following values

No. of trophies = 3

Total Legos required for all trophies = 324

No. of Legos for largest trophy(A) = 220

No. of Legos for smallest trophy(B) = 135

No. of Legos required for final trophy(C) which is unknown

Total legos will addition of everything

Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]

Substituting the values

324 = 220 +135 + C

Making C subject of formula

324 = 355 + C

324 - 355 = C

-31 = C

135 + 31 = 166

We have 166 As the answer

8 0
3 years ago
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