If y=3x+1 were changed to y=x+1, how would the graph of the new function compare with the original?

Mathematics

2 answers:

Tresset [83]3 years ago

6 0

Hello!

A slope intercept form of a line is y = mx + b

m is the slope
b is the y-intercept

since everything is the same but the slopes we know that the answer is either steeper or not as steep

The slope decreases which means the line is not as steep

The answer is C) It would be less steep

Hope this helps!

Yuri [45]3 years ago

4 0

Slope would be 3 times less steep.

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Which of the following graphs represents the function f(x) = x4 - 2x3 - 3x2 + 4x + 1?

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Answer: Graph D will be correct graph for the given function.

Explanation:

Given function $f(x) = x^4-2x^3-3x^2+4x+1$

Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.

Moreover, the degree of the function is even thus the end behavior of the function is $f(x)\to+\infty$ , as $x\to-\infty$ and $f(x)\to+\infty$ as $x\to+\infty$

In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph $f(x)\to-\infty$ , as $x\to-\infty$ and $f(x)\to-\infty$ , as $x\to+\infty$ .) so, it can not be the graph of given function.

In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph $f(x)\to+\infty$ as $x\to-\infty$ and $f(x)\to-\infty$ as $x\to+\infty$ .) so, it can not be the graph of given function.

In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph $f(x)\to-\infty$ as $x\to-\infty$ and $f(x)\to+\infty$ as $x\to\infty$ .) so, it also can not be the graph of given function.