PLZ HELP NNOOOOOOOWW!! 15 points!!

1 answer:

4 0

The midpoint of the line having the endpoints $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_{1}+_x_{2}}{2}, \frac{y_{1}+_y_{2}}{2})$
basically average them

so given that the line has the endpoints of (-3,7) and (9,-2)
x₁=-3
y₁=7
x₂=9
y₂=-2

so the midpoint can be found by doing
$(\frac{-3+9}{2}, \frac{7+(-2)}{2})=$
$(\frac{6}{2}, \frac{7-2}{2})=$
$(3, \frac{5}{2})$

the midpoint is $(3,\frac{5}{2})$

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Find the length of the third side. If necessary, round to the nearest tenth.

NikAS [45]

Use the Pythagorean theorem

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Side = sqrt(28)

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7 0

3 years ago

Read 2 more answers

Kindly answer this question it would be really helpfull

Svetach [21]

Answer:

The values in the table, taking into account the quadratic equation, are:

x -3 -2 -1 0 1 2 3 4
y 16 9 4 1 0 1 4 9

Step-by-step explanation:

To obtain the values of the table, you must use the quadratic equation given:

y = x^2 - 2x + 1

Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:

y = x^2 - 2x + 1
y = (-3)^2 - 2*(-3) + 1
y = 9 + 6 + 1
y = 16

When x is -1

y = x^2 - 2x + 1
y = (-1)^2 - 2*(-1) + 1
y = 1 + 2 + 1
y = 4

When x is 1

y = x^2 - 2x + 1
y = (1)^2 - 2*(1) + 1
y = 1 - 2 + 1
y = 0

When x is 3:

y = x^2 - 2x + 1
y = (3)^2 - 2*(3) + 1
y = 9 - 6 + 1
y = 4

At last, the graph must be as the attached picture I give you, but remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider.