Answer:
B
Step-by-step explanation:
x^2=3x-2(subtract 3x and add 2) x^2-3x+2=0(group) (x-1)(x-2)=0(find x) x=1;x=2
find y values for x values and check:
1^2=1, pair 1:(1,1); 3(1)-2=3-2=1, same pair
2^2=4, pair 2:(2,4); 3(2)-2=6-2=4, same pair
pairs: (1,1);(2,4)
Answer:
Step-by-step explanation:
An eigenvalue of n × n is a function of a scalar
considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =
Suppose the matrix ![A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%26-1%5C%5C2%261%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Thus, the equation of the determinant (A -
1) = 0
This implies that:
![\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1-%5Clambda%20%26-1%5C%5C2%261-%20%5Clambda%5C%5C%20%5Cend%7Barray%7D%5Cright%5D%20%3D0)



Hence, the eigenvalues of the equation are 
Also, the eigenvalues can be said to be complex numbers.
Answer:
D
Step-by-step explanation:
Answer: D
Step-by-step explanation: they Match because same length=congruent
9514 1404 393
Answer:
Step-by-step explanation:
Using the least common denominator, we have ...

The values of a and b are ...
a = 3
b = -18