Where is the picture??? maybe i can help out
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

Using the quadratic formula, the solution for our problem is

The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have

The root is

Then, the maximum height is

1029.99 meters above sea level.
Answer:
K would be 375.
Step-by-step explanation:
You take the number you already have and divide it by the new number its giving. (0.06)
Answer:
41 1/4
Step-by-step explanation:
Change 16 1/2 to a mixed number
16 1/2 = (2*16+1)/2 = 33/2
Change 2 1/2 to a mixed number = (2*2+1)/2 = 5/2
Multiply the turns per inch by the inches
33/2 * 5/2 =165/4
Change this back to a mixed number
4 goes into 165 41 times
41*4 = 164 there is 1 left over
41 1/4