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katrin2010 [14]

2 years ago

11

What is the measure of Angle z?

1 answer:

denis-greek [22]2 years ago

8 0

Answer:

Angle z makes a 180° angle when added to the angle of 124° in the first image, because they are on the same side of a straight line. Just subtract 124 from 180. =56 For the second picture, angle m will be the same as angle z because of the properties involved.

Step-by-step explanation:

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-3( 2u + 5 ) +3.5u = -1u solve the equation

lora16 [44]

Answer:

that conclude idk

Step-by-step explanation:

-6U+-15+3.5U=-1U

-2.5U+15

4 0

3 years ago

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katen-ka-za [31]

The answer to this would be O

5 0

3 years ago

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dlinn [17]

Answer:

18

Step-by-step explanation:

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2 years ago

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Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Solve for n <br>n+1 3/5 =3 3/10

RoseWind [281]

The answer is N=17/10

8 0

3 years ago