Hello :
by idetity : 1+cos(2a) = 2cos²(a)
let : a = <span>θ/2
1+cos(2×</span>θ/2)=2cos²(θ/2)
1+cos(θ) = 2cos²(θ/2)
solve : 2 cos^2 (θ/2) - 3 cos(θ) = 0 ......(1)
(1) : 1+cos(θ)-3 cos(θ) =0
2cos(θ) = 1
cos(θ) = 1/2
in : [0, 2π<span>[
</span>( θ = π/3) or (θ = 5π/3)
Answer:
x = 7/3
Step-by-step explanation:
<u>Given equation:</u>
To determine the value of "x", we need to isolate the x-variable and it's coefficient on one side of the equation. This can be done by subtracting 49 to both sides of the equation.
- ⇒ –9x² + 49 - 49 = 0 - 49
- ⇒ –9x² = -49
We can see that the negative sign in on both sides of the equation. Remove it by dividing -1 to both sides of the equation.
- ⇒ –9x² = -49
- ⇒ -9x²/-1 = -49/-1
- ⇒ 9x² = 49
Clearly, we can see that 9x² and 49 are perfect squares. Therefore,
Take square root both sides of the equation:
To determine the value of "x", we need to isolate it "completely". This can be done by dividing 3 to both sides of the equation
Therefore, the value of "x" must be 7/3.
0745 legit is 7:45 in military time
Answer:
The rock splashes down when h(t) = 0. Set h(t) = 0 and solve for t using quadratic formula.
0 = − 4.9t^2 + 178t + 325
t = 38.07, -1.74
(Throw away the negative answer, since time can't be negative.)
t = 38.07 sec
Please Mark Brainliest If This Helped!
Answer:
C. <em>3,300</em>
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Step-by-step explanation:
