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Sindrei [870]
3 years ago
10

What is an aproximate estimate for 98.7 , 35.4 , 3.8 , 20.3

Mathematics
1 answer:
Helen [10]3 years ago
8 0
99 35, 4, and 20 if it is 5 and up round up. or if you want round up by tens it would be 100, 40, 1, 20
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Zoey made 6 3/4 cups of fruit salad for a picnic. At the picnic, they ate 1/3 of the fruit salad. How much of the fruit salad di
Aleks04 [339]

Answer:

9/4 cups

Step-by-step explanation:

6 3/4 = 27/4

27/4 * 1/3 = 27/12

27/12 = 9/4

4 0
3 years ago
Solve 6x + 2 = 5x + 17 for x if there is a solution.
labwork [276]

Answer: x=15


Step-by-step explanation:

To solve problems like this you need to simplify the equations on both sides and then isolate your variable x.


3 0
3 years ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
the cost of jeans is $55.56. choose the value that produces a mark down A.)$54.32. B.)$75.40 C) $57.49 D)$55.70​
Alona [7]
I would say A.$54.32 because it is the only option that is less than 55.56
7 0
3 years ago
Find the value of x round to the nearest tenth 20 35
Norma-Jean [14]
What is the equation ?
4 0
3 years ago
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