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3 years ago

40-9x+4x+5 with combining like terms

Mathematics

2 answers:

amid [387]3 years ago

4 0

Answer:

40-9x+4x+5=

45-5x

You can't do anything else because the variables are different.

Marina CMI [18]3 years ago

3 0

Answer:

-5x + 45

Step-by-step explanation:

40 - 9x + 4x + 5

you combine like terms

Coefficient + Coefficient ( -9x + 4x)

and

Constant + Constant ( 40 + 5 )

-5x + 45

since there isn't an equal sign you can't solve for x and this is as close as you can get to solved without knowing what x is

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What integer represent 11 degrees above zero?

Vikki [24]

It would be 11 since an integer above zero is positive and an integer below zero is a negative

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3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints are (1,-3)(1,−3) and (7,-7)(7,−7).

Alborosie

Answer:

$y=\frac{3}{2} x-11[$

Step-by-step explanation:

$y-\frac{-7-3}{2} =\frac{-1}{\frac{-7-(-3)}{7-1} } (x-\frac{7+1}{2} )\\y+5=\frac{6}{4} (x-4)\\y=\frac{3}{2} x-11[$

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3 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under

Shkiper50 [21]

The work is equal to the line integral of $\vec F$ over each line segment.

Parameterize the paths

from (0, 0, 0) to (2, 0, 0) by $\vec r_1(t)=t\,\vec\imath$ with $0\le t\le2$ ,
from (2, 0, 0) to (2, 4, 1) by $\vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k$ with $0\le t\le1$ ,
from (2, 4, 1) to (0, 4, 1) by $\vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k$ with $0\le t\le2$ , and
from (0, 4, 1) to (0, 0, 0) by $\vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k$ with $0\le t\le1$

The work done by $\vec F$ over each segment (call them $C_1,\ldots,C_4$ ) is

$\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0$

$\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3$

$\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2$

$\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3$

Then the total work done by $\vec F$ over the particle's path is 46.

8 0

4 years ago

Help please!!! i dont get it

IgorLugansk [536]

The amount of money in the account if compounded quarterly at 6% after 9 years is $22,217

<h3>Compound interest</h3>

Principal, P = $13,000
Time, t = 9 years
Interest rate, r = 6% = 0.06
Number of periods, n = 4

A = P(1 + r/n)^nt

= 13,000(1 + 0.06/4)^4×9

= 13,000(1 + 0.015)^36

= 13,000(1.015)^36

= 13000(1.709)

= $22,217

Learn more about compound interest:

brainly.com/question/24924853

#SPJ1

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2 years ago

Jane needs to make a four-letter password. If the first letter has to be a vowel, how many possibilities are there to choose fro

Alexus [3.1K]

The vowels are A,E,I,O,U so 5 because if you add them together it’s 5

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3 years ago