2x-21+6=x-3. How would you solve this

Dracula has 48 pieces of candy. He gave ⅓ of his candy to his friend and 25% of his candy to his cousin. How many pieces of cand

Natali5045456 [20]

Answer:

Dracula will be left with 24 candies

Step-by-step explanation:

The given problem is of fractions and percentages.

Given that

Total pieces of candy = 48

Now as it is mentioned that Dracula gives 1/3 of his candies to his friend, wee have to find the one third of the total pieces of candies first.

$one-third\ of\ candies = \frac{1}{3} * 48\\= 16$

Dracula will be left with:

$Candies\ left = Total\ candies - one\ third\ of\ candies\\= 48-16 = 32$

Dracula will be left with 32 candies after giving one third to his friend.

Now he gives 25% of remaining to his cousin

So,

$25\%\ of\ 32\\= \frac{25}{100}*32\\=8$

Dracula will be left with: 32-8 = 24 candies

Hence,

Dracula will be left with 24 candies

5 0

3 years ago

Can someone please explain the Pythagorean theorem to me?

Leona [35]

Answer:

Pythagoras theorem is is a mathematical law that states that the sum of squares of the lengths of the two short sides of the right triangle is equal to the square of the length of the hypotenuse.

Step-by-step explanation:

The hypotenuse is the side opposite to the right angle and so the equation for finding the hypotenuse would be:

a^2+^b^2=c^2

7 0

3 years ago

GEOMETRY 15 POINTS PLEASE HELP

zhuklara [117]

Answer:

y is four:)

Step-by-step explanation:

7y+5 = 9y-3

7y+8 = 9y

8 = 2y

4 = y

5 0

3 years ago

7. Simplify the following as much as possible.<br> Simplify x/3 +x/4

Alla [95]

Answer:

$\frac{7x}{12}$

Step-by-step explanation:

Before adding the fractions we require them to have a common denominator.

Multiply the numerator/ denominator of the first fraction by 4

Multiply the numerator/ denominator of the second fraction by 3

$\frac{4x}{12}$ + $\frac{3x}{12}$

Now add the numerators leaving the denominator

= $\frac{4x+3x}{12}$

= $\frac{7x}{12}$

7 0

3 years ago

Read 2 more answers

Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a standard deviation of 900

rosijanka [135]

Answer:

The 33 week gestation period baby has a zscore of -0.47.

The 41 week gestation period baby has a zscore of -0.94.

The 41 week gestation period baby weighs less relative to the gestation period.

Step-by-step explanation:

Normal model problems can be solved by the zscore formula.

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

The zscore represents how many standard deviations the value of X is above or below the mean $\mu$ . This means that the baby with the lowest Zscore is the one who weighs relatively less to the gestation period.

33 week gestation period baby:

Babies born after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a standard deviation of 900 grams, so $\mu = 2700, \sigma = 900$ .

A 33-week gestation period baby weighs 2275 grams. So $X = 2275$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2275 - 2700}{900}$

$Z = -0.47$

41 week gestation period baby:

Babies born after a gestation period of 40 weeks have a mean weight of 3200 grams and a standard deviation of 450 grams, so $\mu = 3200, \sigma = 450$

A 41-week gestation period baby weighs 2775 grams, so $X = 2775$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2775 - 3200}{450}$

$Z = -0.94$

The 41 week gestation period baby weighs less relative to the gestation period, since he has a lower zscore.

8 0

3 years ago