Is f(x)=e^2 an exponential function? If so what is its base? If not, why?

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

Answer:

No. It is a constant function.

Step-by-step explanation:

The function f(x) = e^2 is not an exponential functional. Rather, it is a constant function. The reason for this is that in f(x) = e^2, there is no x involved on the right hand side of the equation. The approximate value of e is 2.718281, and the approximate value of 2.718281^2 is 7.389051. This means that f(x) = e^2 = 7.389051. It is important to note that for any value of x, the value of the function remains fixed. This is because the function does not involve the variable x in it. The graph of the function will be a line parallel to the x-axis, and the y-intercept will be 7.389051. For all the lines parallel to x-axis, the value of the function remains the same irrespective of the value of x. Also, the derivative of the function with respect to x is 0, which means that the value of the function is unaffected by the change in the value of x!!!

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classify each angle pair using all the names that apply using the diagram on the left , answering 1 2 3 4 and 5 , explain why.(

vredina [299]

Answer:

see the attachment

Step-by-step explanation:

1. Two angles that sum to 90° are complementary, whether they are adjacent or not. Angles LMN and NMP are also adjacent.

2. Vertical angles created by two distinct lines are never adjacent. The sides of the angles are created by the same lines, and the angles share a vertex, but there is no ray that is a side common to both angles.

3. Angle GMK is supplementary to angle JMG.

4. Vertical angles are congruent. See question 2.

5. See question 1.