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Sphinxa [80]
4 years ago
5

Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4

Mathematics
1 answer:
crimeas [40]4 years ago
8 0

We have been given an expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}. We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, a^m\cdot a^n=a^{m+n}, we cab rewrite our given expression as:

\left( 4^{-2+(-3)} \right)^{3}

\left( 4^{-5} \right)^{3}

Now we will use exponent property (a^m)^n=a^{m\cdot n}to further simplify our expression.

\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}

\left( 4^{-5} \right)^{3}= 4^{-15}

Therefore, Chris made mistake in step 2.

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Answer: 7) Max: y = 52

               8) Min: y = -51  

<u>Step-by-step explanation:</u>

The Max/Min is the y-value of the intercept.

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  • Min is when the a-value is positive.

First, find the x-value of the vertex using the Axis of Symmetry formula:

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7) y = -2x² - 16x + 20

          ↓       ↓       ↓

     a= -2   b= -16  c=20

\text{AOS:}\quad x=\dfrac{-b}{2a}\quad =\dfrac{-(-16)}{2(-2)}\quad =\dfrac{16}{-4}\quad =-4

Max: y = -2(-4)² - 16(-4) + 20

           = -2(16) + 64 + 20

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          = 52

*********************************************************************************************

7) y = x² + 12x - 15

        ↓      ↓      ↓

   a= 1   b= 12  c= -15

\text{AOS:}\quad x=\dfrac{-b}{2a}\quad =\dfrac{-(12)}{2(1)}\quad =\dfrac{-12}{2}\quad =-6

Max: y = (-6)² + 12(-6) - 15

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           = 36 - 87

          = -51

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