All categories

3 years ago

The median is the same as the ______________.

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

Answer: Option A

The median is the same as the _ Second quartile_.

Step-by-step explanation:

Given a series of data ordered from least to greatest, the median is the value that is in the center.

That is, the median represents the value that divides 50% of the data.

In the same way, the first quartile $Q_1$ is the value that divides 25% of the data and the third quartile $Q_3$ is the value that divides 75% of the data.

The second quartile $Q_2$ is the number that divides 50% of the data.

Then notice that the second quartile is equal to the median

Then te answer is the option A.

xeze [42]3 years ago

3 0

Answer:

A. Second quartile

Step-by-step explanation:

Median is the middle value of the data when arranged, it divides the data in two halves.

Also second quartile is the point in data that divides the data into two quarters.

Hence second quartile is median of data!

You might be interested in

-3(8+j)=-16+5j<br> HELP ASAP NEED THIS DONE TONIGHT BEFORE MIDNIGHT

iogann1982 [59]

Answer:

j = -1

Step-by-step explanation:

Eliminate parentheses:

-24 -3j = -16 +5j

Add 3j+16

-8 = 8j

Divide by the coefficient of j.

-1 = j

8 0

2 years ago

Read 2 more answers

2) Which expressions are equivalent to 1/3 - (-1/4). Select all that apply.

marshall27 [118]

What are all that apply?

8 0

3 years ago

Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.

Ann [662]

Given:

Consider the given function is:

$f(x)=x^2-8x+13$

To find:

The average rate of change of the function over the interval $-1\leq x\leq 6$ .

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

$m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

We have,

$f(x)=x^2-8x+13$

At $x=-1$ ,

$f(-1)=(-1)^2-8(-1)+13$

$f(-1)=1+8+13$

$f(-1)=22$

At $x=6$ ,

$f(6)=(6)^2-8(6)+13$

$f(6)=36-48+13$

$f(6)=1$

Now, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is:

$m=\dfrac{f(6)-f(-1)}{6-(-1)}$

$m=\dfrac{1-22}{7}$

$m=\dfrac{-21}{7}$

$m=-3$

Therefore, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is -3.

6 0

3 years ago

To test μ for an x distribution that is mound-shaped using sample size n ≥ 30, how do you decide whether to use the normal or st

Luden [163]

Answer:
Use the normal distribution if the population standard deviation is known.
Use the student's t distribution when the population standard deviation is unknown.

Explanation:
A mound-shaped distribution refers to the normal distribution.
A good sample size for testing against the normal distribution should be
n >= 30.
The condition for the sample size is satisfied.
However, we are not given the population standard deviation, therefore it is assumed to be unknown.
Therefore the student's t distribution should be used.

6 0

3 years ago

Use the graph of the quadratic function y = - 1x2 + x + 4 to

True [87]

Answer: A, -2 and 4

Step-by-step explanation: cause it it you’re welcome

6 0

3 years ago