Answer:
7 square units
Step-by-step explanation:
As with many geometry problems, there are several ways you can work this.
Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.
The applicable formulas are ...
area of a trapezoid: A = (1/2)(b1 +b2)h
area of a triangle: A = (1/2)bh
So, our areas are ...
AQRS = AWSQE - AWSR - AEQR
= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)
Factoring out 1/2, we have ...
= (1/2)((2+5)·4 -2·2 -5·2)
= (1/2)(28 -4 -10) = 7 . . . . square units
Use a box. Split the terms into the boxes and then multiply across. Sort of like area multiplication, only with terms.
3 5x
4y 12y 20xy
3 9 15x
Attached the solution and work.
Answer:
B. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Symmetric Property of Equality
Step-by-step explanation:
Given expression,
By substituting x = 8,
By subtraction property of equality,
Division property of equality,
By symmetric property of equality,
Answer:
there isn't really an answer
Step-by-step explanation:
use the greatest common denominator (12) for all of them
for 3/12 you dont have to change it,
for 1/6 multiply it by 2, (2/12)
for 1/3 multiply it by 4, (4/12
The least is 2/12 or 1/6
then comes 3/12
then the greatest is 4/12 or 1/3
-plz mark brainliest-
