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Papessa [141]
4 years ago
9

A bag contains 6 red marbles, 3 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probabi

lity, to the nearest 10th of a percent, that all three marbles drawn will be green?
Mathematics
1 answer:
ale4655 [162]4 years ago
3 0

This is a 4 step problem.

Find the probability of drawing a green marble the first time

<em>8 green marbles ÷ 17 total marbles </em>

Next, we find the probability of drawing a green marble the second time

<em>7 green marbles ÷ 16 total marbles </em>

Find the probability of drawing a green marble the third time

<em>6 green marbles ÷ 15 total marbles </em>

We<u> take away one</u> from the total marbles and green marbles each time because we are finding the probability that we draw a green marble <u>all three times </u>

Last step:

Multiply all the probabilities

\frac{8}{17} × \frac{7}{16} × \frac{6}{15}

The final answer is 7/85 or an 8% chance

If you were curious, the decimal version of this answer is <u>0.08235294</u>

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A temperature falls from 0 to  - 12\dfrac{1}{4}     in     3\dfrac{1}{2} \ hours

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From the above given information;

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The change in temperature is \Delta T = T_2  -  T_1

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The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

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