Question

The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the change in temperature per hour?

Answer 1

Answer:

The expression used to find the change in temperature per hour is Algebraic expression

Thus per hour; the temperature falls at the rate of $- 3\dfrac{1}{2}^0$

Step-by-step explanation:

A temperature falls from 0 to  $- 12\dfrac{1}{4}$     in     $3\dfrac{1}{2} \ hours$

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is  $- 12\dfrac{1}{4}$  

The change in temperature is $\Delta T = T_2 - T_1$

$\Delta T = -12\dfrac{1}{4} -0$

$\Delta T = -12.25$

Thus;

-12.25 ° = 3.5 hours

To find the change in x°   per hour; we have;

x°            = 1 hour

The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

$\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}$

x° =  - 3.5

x° = $- 3\dfrac{1}{2}$

Thus per hour; the temperature falls at the rate of $- 3\dfrac{1}{2}^0$