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3 years ago

Which is the approximate circumference of a circle with a diameter of 60 cm?

1 answer:

8 0

The circumference is the diameter times pi.

$d=60 \ [cm] \\ \\
C=60\pi \approx 60 \times 3.14=188.4 \approx 188 \ [cm]$

The answer is D.

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Find the probability of rolling a seven first and then a four when a pair of dice is rolled twice

luda_lava [24]

Answer:

1/72

Step by step:

The probability of rolling a seven is 1/6 as there are 36 combinations you can roll on two dice, and six of them add up to 7. The probability of rolling a 4 is 1/12 as there are 3 ways to roll a 4. Multiplying these together you get 1/72.

3 0

4 years ago

Read 2 more answers

A random sample of 384 people in a mid-sized city (city one) revealed 112 individuals who worked at more than one job. A second

Svetlanka [38]

Answer:

99% confidence interval is:

(0.00278 < P1 - P2< 0.15921)

Step-by-step explanation:

For calculating a confidence intervale for the difference between the proportions of workers in the two cities, we calculate the following:

$[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }$

Where $p_{1}$ : proportion sample of individuals who worked

at more than one job in the city one

$n_{1}$ : Number of respondents in the city one

$p_{1}$ : proportion sample of individuals who worked

at more than one job in the city two

$n_{1}$ : Number of respondents in the city two

Then

α = 0.01 and α/2 = 0.005

and $z_{\alpha/2} = 2.575$

$p_{1} = \frac{112}{384} = 0.2916$

$p_{2} = \frac{91}{432} = 0.2106$

$n_{1}= 384$ and $n_{2}= 432$

The confidence interval is:

$[(0.2916 - 0.2106) \pm 2.575 \sqrt{\frac{0.2916(1-0.2916)}{384} + \frac{0.2106(1-0.2106)}{432} }$

(0.00278 < P1 - P2< 0.15921)

5 0

3 years ago

Please answer ASAP and if you do you will get Brainliest. Catherine buys a gallon of ice cream from the store. After taking it h

rodikova [14]

Answer:

Catherine's sister ate 2/15 gallons of the ice cream.

$\displaystyle \frac{2}{15}$ .

Step-by-step explanation:

Let $x$ be the amount of ice cream that Catherine's sister ate, in gallons.

Original amount: 1 gallon.

What Catherine ate: $\displaystyle \frac{1}{5}$ gallons.
What Catherine's sister ate is assumed to be $x$ gallons.

What's left: $\displaystyle \frac{2}{3}$ gallons.

Consider the relationship:

$\text{Original amount - What Catherine ate - What Catherine's Sister ate}\\ =\text{ What's left.}$ .

That is:

$\displaystyle 1- \frac{1}{5} - x = \frac{2}{3}$ .

Add $x$ to both sides of this equation:

$\displaystyle 1 - \frac{1}{5} = \frac{2}{3} +x$

Substract $\displaystyle \frac{2}{3}$ from both sides:

$\displaystyle 1 - \frac{1}{5} - \frac{2}{3} = x$ .

Convert the denominator of all three numbers on the left-hand side to $3 \times 5 = 15$

$\displaystyle \frac{15}{15} - \frac{3}{15} - \frac{10}{15} = x$ .

$\displaystyle x = \frac{2}{15}$ .

In other words, Catherine's sister ate $\displaystyle \frac{2}{15}$ gallons of the ice cream.

3 0

3 years ago

Read 2 more answers

TV=3x-24 and VX=2x+1. What is the value of VX? 1. 25 2. 99 3. 5 4. 51

Maslowich

ΔTXV is an isosceles triangle because ∡T = ∡X therefore TV = VX.

3x - 24 = 2x + 1 |subtract 2x from both sides

x - 24 = 1 |add 24 to both sides

x = 25

7 0

3 years ago

Read 2 more answers

Which of the following describes the relationship between the area of a rectangle and its width, as width varies and length stay

sergejj [24]

I think the correct answer from the choices listed above is option C. The relationship between the area of a rectangle and its width, as width varies and length stays the same, would be that as width decreases, area decreases. Hope this answers the question. Have a nice day.

3 0

3 years ago