2 years ago

Y=4x^3+3x^2-2x+9.=> y'=?

Mathematics

1 answer:

-Dominant- [34]2 years ago

4 0

Step-by-step explanation:

y'=dy/dx=d/dx(4x³+3x²-2x+9)

=(3*4x^(3-1)+2*3x^(2-1)-2*1x^(1-1)+9*0

y'=12x²+6x-2

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Y=4x^3+3x^2-2x+9.=> y'=?​

Y=4x^3+3x^2-2x+9.=> y'=?