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scoundrel [369]
3 years ago
9

Y=4x^3+3x^2-2x+9.=> y'=?​

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Step-by-step explanation:

y'=dy/dx=d/dx(4x³+3x²-2x+9)

=(3*4x^(3-1)+2*3x^(2-1)-2*1x^(1-1)+9*0

y'=12x²+6x-2

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