The answer is 0.4%. The probability that a unit end in a rework can be calculated using the following equation:
P(rework)= P(defects found) * P(defect)
= .8 * .005
= .004
= 0.4%
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The answer is C: 
Starting with the given formula for the area, A = 1/2hb, the first step is to isolate h by using the multiplicative inverse of b, which is 
on both sides of the equation:
The result will be:
The last step is to use the multiplicative inverse of 
, which is 2 or 
to further isolate the variable <em>h </em>:
The formula for h will be:
which is the option C in your question.
Answer:
no it to low
Step-by-step explanation:
the answer was 4998
X= -3
Solution:
takeaway 4 from each side
x+3=0
subtract 3 from each side
x=-3
