Given:
The variance of a distribution = 195.
To find:
The standard deviation, rounded to the nearest thousandth.
Solution:
Standard deviation of a distribution is the square root of the variance of the distribution.
Here, the standard deviation of the distribution is
Therefore, the standard deviation is 13.964.
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
5/9
Step-by-step explanation:
complement means not choosing an orange
P( not choosing orange) = (apple and fruit) / total
= (4+6) / (4+6+8)
=10/18
= 5/9
Answer:
-12
Step-by-step explanation:
(-2)(-3)^2-2(2-5). Original
-2(9)-2(2-5) Distribute Exponents
-18-4+10 Distribute Parentheses
-22+10 Do subtraction
-12 Do Addition
