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Ghella [55]
3 years ago
9

Plz helps it's due today​

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

The sine of an angle is the length of the leg farthest away from the angle divided by the length of the hypotenuse.

The length of the leg farthest from angle O is 20, and the length of the hypotenuse is 52. With this information, we find that:

\sin(\angle O)=\dfrac{20}{52}

We can simplify this fraction into:

=\dfrac{5}{13}

That's your answer. Let me know if you need any clarifications, thanks!

~ Padoru

Marysya12 [62]3 years ago
5 0

\sin(o)  =  \frac{20}{52}  \\  \\  \sin(o)  =  \frac{5}{13}

You might be interested in
Tax returns filed manually have a 20% chance of containing errors, while tax returns filed electronically have a 0.05% chance of
suter [353]

Answer:

B) 538, 650

Step-by-step explanation:

Given:

Errors on tax returns filed manually  = 20%

Errors on tax returns filed electronically  = 0.05%

Tax return filled in each way = 2.7 million

Manual filing:

2,700,000 x 20% = 2,700,000*0.2 = 540,000

Electronic filing:

2,700,000 x 0.05% = 2, 700,000*0.0005 = 1,350


Error difference = 540,000 - 1,350 = 538,650

There will be 538,650 more erroneous tax returns filed manually than there are filed electronically.

Thank you.

3 0
3 years ago
Read 2 more answers
Ms.Lamberson got a new puppy abd weighed it in September and October in September the Puppy Weighed9 and one Fourth pounds In Oc
ddd [48]

Answer: The puppy was 2.25\ lb havier in October that it was in September.

Step-by-step explanation:

You need to make the conversion from mixed numbers to decimal numbers. To do it, divide the numerator of the fraction by the denominator add the result to whole part number:

9\frac{1}{4}=9+0.25=9.25\\\\11\frac{1}{2}=11+0.5=11.5

The weight of the puppy in September was:

w_1=9.25\ lb

And its weight in October was:

w_2=11.5\ lb

Subtract its weight in September from its weight in October in order to find how much heavier the puppy was in October than it was in September:

w_2-w_1=11.5\ lb-9.25\ lb=2.25\ lb

8 0
3 years ago
What is the area? Round to the nearest tenth
Tamiku [17]

Answer:

60.8 mm^2

D

Step-by-step explanation:

Remark

You have to assume that the left and right sides are both 9.3. The question is undoable without that assumption.

Next, you have to assume that The top is 7.8 mm across and both ends meet 9.3 at right angles. Again if that is not true, the problem can't be done. Sometimes people making these questions make errors which you are asked to correct.

Solution

So let's assume that everything I've assumed is correct.

Find the area of the rectangle.

Area = L*W

L = 9.3

W = 7.8

Area = 7.8 * 9.3

Area = 72.54        Do your rounding at the end.

Now find the are of the triangle that has been cut out.

The height = 3

The base = 7.8

Area = 1/2 b * h

Area = 1/2 7.8 * 3

Area = 11.7

The area of the figure = area of the rectangle - the triangle's area

Figure Area = 72.54 - 11.7

Figure Area = 60.84

6 0
3 years ago
Kim has a a coin and a dice with 6 sides. She flips the coin once and rolls the dice once. What is the probability that the coin
TEA [102]

Answer:

10

Step-by-step explanation:

6+4=10

3 0
2 years ago
Read 2 more answers
From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.
Firdavs [7]

Answer:

a. 360.323 m

b. 95.265^{o}

Step-by-step explanation:

Distance covered from A to B = speed x time

                                                 = 110 x 2.8

                                                 = 308 m

Distance covered from B to C = speed x time

                                                  = 110 x 1.7

                                                  = 187 m

The sum of angles at B = 64^{o} + 26^{o}

                                       = 90^{o}

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

Sot hat;

b^{2} = 187^{2} + 308^{2} - 2(187 x 308) Cos 90^{o}

But, Cos 90^{o} = 0

So that,

b^{2} = 187^{2} + 308^{2}

  = 34969 + 94864

  = 129833

b = \sqrt{129833}

  = 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{187}{SinA} = \frac{360.323}{Sin90^{o} }

\frac{187}{SinA} = \frac{360.323}{1}

Sin A = \frac{187}{360.323}

         = 0.5190

⇒ A = Sin^{-1} 0.5190

       = 31.265^{o}

The bearing of the plane from its original location = 64^{o} + 31.265^{o}

                                                     = 95.265^{o}

8 0
3 years ago
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