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Mamont248 [21]
2 years ago
9

The histogram shows the weights, in pounds, of checked luggage on a flight. The median weight of a checked bag is 27.5 pounds. H

ow does the mean of the data most likely compare to the median? The mean is most likely less than 27 pounds. The mean is most likely exactly 27.5 pounds. The mean is most likely about 28 pounds. The mean is most likely more than 28 pounds.

Mathematics
1 answer:
Darya [45]2 years ago
8 0

Answer: C, the mean is most likely about 28 lbs.

Step-by-step explanation: The mean of a data set is the average value. When looking at this histogram, you can determine how many bags were checked in  total by adding up the frequencies for each weight.

<u>Add the Weights </u>

1+16(4)+20(5)+24(6)+28(5)+32(4)+36(3)+40+48+52+56+60

**16(4)=64. The number in parenthesis represents how many times each weight occurred in the data set. To make it easier, you can combine some of these instead of typing the extended equation into your calculator.

12+64+100+144+140+128+108+208= 904

<u>Solve for the Mean</u>

<u></u>

To do this, divide 904 by the number of bags checked (32).

Mean: 28.25

**The answer is MORE than 28, but it would round down because the decimal is less than half.

Hope this helps,

LaciaMelodii :)

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How to work out 12.5% of a number
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Step-by-step explanation:

12.5÷100 × 5

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2 years ago
A Martian couple has children until they have 2 males (sexes of children are independent). Compute the expected number of childr
Ne4ueva [31]

Answer:

a) 6

b) 4

c) 3

Step-by-step explanation:

Let p be the probability of having a female Martian, and of course, 1-p the probability of having a male Martian.

To compute the expected total number of trials before 2 males are born, imagine an experiment simulating the fact that 2 males are born is performed n times.

Let ak be the number of trials performed until 2 males are born in experiment k. That is,

a1= number of trials performed until 2 males are born in experiment 1

a2= number of trials performed until 2 males are born in experiment 2

and so on.

If a1 + a2 + … + an = N

we would expect Np females.  

Since the experiment was performed n times, there 2n males (recall that the experiment stops when 2 males are born).

So we would expect 2n = N(1-p), or

N/n = 2/(1-p)

But N/n is the average number of trials per experiment, that is, the expectation.

<em>We have then that the expected number of trials before 2 males are born is 2/(1-p) where p is the probability of having a female. </em>

a)

Here we have the probability of having a male is half as likely as females. So

1-p = p/2 hence p=2/3

The expected number of trials would be

2/(1-2/3) = 2/(1/3) =6

This means <em>the couple would have 6 children</em>: 4 females (the first 4 trials) and 2 males (the last 2 trials).

b)

Here the probability of having a female = probability of having a male = 1/2

The expected number of trials would be

2/(1/2) = 4

This means<em> the couple would have 4 children</em>: 2 females (the first 2 trials) and 2 males (the last 2 trials).

c)

Here, 1-p = 2p so p=1/3

The expected number of trials would be

2/(1-1/3) = 2/(2/3) = 6/2 =3

This means<em> the couple would have 3 children</em>: 1 female (the first trial) and 2 males (the last 2 trials).

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Answer:

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760x40=30,400

30,400 divided by 100=304

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