Answer:
Total number of possible combinations are 6
Length width
23 dm 2m
21 dm 4 dm
19 dm 6 dm
17 dm 8 dm
15 dm 10 dm
13 dm 12 dm
Step-by-step explanation:
We are given that
Perimeter of rectangular garden=50 dm
Width is even number.
Length is always longer than or equal to width.
Let length of rectangular garden=x
Width of rectangular garden=y
We have to find the possible number of combinations .
Perimeter of rectangular garden=



If y=2 dm
x=25-2=23 dm
If y=4 dm
x=25-4=21 dm
If y=6 dm
x=25-6=19 dm
If y=8 dm
x=25-8=17 dm
If y=10 dm
x=25-10=15 dm
If y=12 dm
x=25-12=13 dm
If y=14 dm
x=25-14=11 dm
x<y
It is not possible
Then, possible combinations are 6
Length width
23 dm 2m
21 dm 4 dm
19 dm 6 dm
17 dm 8 dm
15 dm 10 dm
13 dm 12 dm
It would be D
Your welcome ;)
Answer:
36
Step-by-step explanation:
Flip your eq. x/3 + 6 = 18.
Solve (Number on one, variable on other)
+6 -6 = 0. 18-6=12.
Multiply.
12 * 3 = 36.
3(-1) + 5y = 17
add 3 to both sides
5y=20
divide by 5
y=4
Answer:
length = 3x = 3 × 11 = 33 m
breadth = 2x = 2 × 11 = 22 m
Step-by-step explanation:
here's the solution :-
let's take the ratio constants be x
so, length = 3x
breadth = 2x
And, we know that area of rectangle =
length × breadth
So,
=》

=》

=》

=》

=》

=》

so, length = 3x = 3 × 11 = 33 m
breadth = 2x = 2 × 11 = 22 m