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shtirl [24]
4 years ago
12

The variable in a relation who’s value depends on the value of the independent variable is called what?

Mathematics
1 answer:
Viefleur [7K]4 years ago
3 0
That is called the dependent variable. It depends upon the value of the independent variable.

f(x)=y

So we can see by inspection that the dependent variable y value depends upon the input value of the independent variable x

Any questions please feel free to ask. Thanks
You might be interested in
Which data set COULD NOT be represented by the box plot shown? A) {13, 5, 8, 8, 6, 10, 15, 12, 4, 13, 11} B) {2, 10, 13, 7, 9, 5
siniylev [52]

Answer:

B

Step-by-step explanation:

From the box plots shown above:

The lowest number is 4

The highest number is 15

Therefore, the values in each boxes must lie between {4,15}.

In option A the values in the box include: {13,5,8,8,6,10,15,12,4,13,11}. The values of this data lies between 4 and 15 which makes it correct.

In the second option(B) the values in the boxes include: {2,10,13,7,9,5,15,12,7,13,11}.

The value 2 is not present in the interval, therefore the set of data is wrong.

In option C the values in the box include: {15,13,6,7,10,8,11,13,13,6,4}.

The values of this data lie between the interval of 4 and 15 which makes it correct.

In option D, the values in the box include: {4,13,6,7,15,12,11,10,5,13,9}·

The values of this data lie between the interval of 4 and 15 which makes it correct.

5 0
3 years ago
Evalueate-2/5-x(-9/10) where x= 4/5​
Xelga [282]

Answer:

i think 8/25

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Six students, A, B, C, D, E, F, are to give speeches to the class. The order of speaking is determined by random selection. Find
postnew [5]

Answer:

a) 16.7% probability that E will speak first.

b) 3.33% probability that C will speak fifth and B will speak last.

c) 0.14% probability that the students will speak in the following order: DECABF.

d) 33.33% probability that A or B will speak first.

Step-by-step explanation:

The first speaker can be any of them. The second can be any of them bar the first. It continues until the last one. So the total number of outcomes is 6! = 720.

(a) E will speak first

The first one to speak is E.

The other five can be selected in any order. So there are 5! = 120 total outcomes in which E speaks first.

There is a 120/720 = 0.167 probability that E will speak first.

(b) that C will speak fifth and B will speak last

The fifth can only be C and the sixth can only be B.

The first four can be selected in any order. So there are 4! = 24 outcomes in which C speaks fifth and B last.

There is a 24/720 = 0.0333 probability that C will speak fifth and B will speak last.

(c) that the students will speak in the following order: DECABF

This is the only possible outcome in this order.

So there is a 1/720 = 0.0014 = 0.14% probability that the students will speak in the following order: DECABF.

(d) that A or B will speak first.

For A first, the following five can be in any order. So there are 5! = 120 outcomes in which A speaks first. The same logic and result for B.

So there are 240 outcomes in which A or B speaks first.

There is a 240/720 = 0.3333 = 33.33% probability that A or B will speak first.

5 0
3 years ago
Can someone help me answer questions
ANEK [815]
Add 6 to both sides
2m2+7m+6=0
5 0
4 years ago
What is 68 divided by 5 ??
FinnZ [79.3K]
68 Divided by 5 is 13.6
5 0
3 years ago
Read 2 more answers
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