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Phoenix [80]
2 years ago
15

Using The diagram, name two pairs of adjacent angles and two pairs of vertical angles.​

Mathematics
1 answer:
Crank2 years ago
3 0

Answer:

1. adjacent: ∠ACB and ∠BCD.

vertical: ∠ACB and ∠ECD

Step-by-step explanation:

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Let divf = 6(5 − x) and 0 ≤ a, b, c ≤ 12. (a) find the flux of f out of the rectangular solid 0 ≤ x ≤ a, 0 ≤ y ≤ b, and 0 ≤ z ≤
dusya [7]
Continuing from the setup in the question linked above (and using the same symbols/variables), we have

\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}(\nabla\cdot f)\,\mathrm dV
=\displaystyle6\int_{z=0}^{z=c}\int_{y=0}^{y=b}\int_{x=0}^{x=a}(5-x)\,\mathrm dx\,\mathrm dy\,\mathrm dz
=\displaystyle6bc\int_0^a(5-x)\,\mathrm dx
=6bc\left(5a-\dfrac{a^2}2\right)=3abc(10-a)

The next part of the question asks to maximize this result - our target function which we'll call g(a,b,c)=3abc(10-a) - subject to 0\le a,b,c\le12.

We can see that g is quadratic in a, so let's complete the square.

g(a,b,c)=-3bc(a^2-10a+25-25)=3bc(25-(a-5)^2)

Since b,c are non-negative, it stands to reason that the total product will be maximized if a-5 vanishes because 25-(a-5)^2 is a parabola with its vertex (a maximum) at (5, 25). Setting a=5, it's clear that the maximum of g will then be attained when b,c are largest, so the largest flux will be attained at (a,b,c)=(5,12,12), which gives a flux of 10,800.
7 0
3 years ago
Based on the net shown below, what is the surface area of the pyramid to the nearest square inch. please show work
-BARSIC- [3]

Pyramid Surface Area = (½ * Perimeter of Base * Slant Height) + Base Area

Perimeter of Base = 6 * 4 = 24
Base Area = 6 * 6 = 36

Pyramid Surface Area = (½ * Perimeter of Base * Slant Height) + Base Area
Pyramid Surface Area = (½ * 24 * 6) + 36
Pyramid Surface Area = 72 + 36
Pyramid Surface Area = 108 square inches


3 0
2 years ago
A car travels at 65 miles per hour. Going through collision,it travels at 3/5 this speed. Write this fraction as a decimal.
solniwko [45]

Answer:

0.6

Step-by-step explanation:

the car moves at a speed of 3/5*65 miles per hour

that is 39 miles per hour

but this has nothing to do with the question as the only fraction is 3/5

6 0
3 years ago
2.1 in a decimal form
Allisa [31]

2.1 is already in a decimal form.

Hope I helped!

7 0
3 years ago
On Monday, the rover traveled 330 cm. On Tuesday,it traveled 180 cm. If the rover stoped every 15 cm to recharge, how many more
boyakko [2]
10 more times

On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10

3 0
3 years ago
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