5c^5 + 60c^4 + 180c^3
find the GCF, 5c³
5c³(5c^5 + 60c^4 + 180c^3/ 5c^3)
5c³(c² + 12c + 36)
5c³(c² + 2(c)(6) + 6²)
5c³(c + 6)² <<< the answer.
hope this helps, God bless!
That would be 2.1 because if it's in decimal it's 2.1
Answer: (0.465, 5.535)
Step-by-step explanation:
Formula to calculate the confidence interval (<em>when population standard deviation is unknown</em>) is given by :-

, where
= sample mean.
s= sample standard deviation.
n= Sample size.
= critical value
By considering the given information , we have
s=0.75
n= 9
Significance level =
[1-0.90=0.1]
By using students' t distribution -table , the critical value for 95% confidence level :

[Note: degree of freedom = n-1]
Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :




Hence, the required confidence interval =(0.465, 5.535)