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Novosadov [1.4K]
3 years ago
13

Answer with a space i don't care

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

...

Step-by-step explanation:

.......................

You might be interested in
The number of bacteria in a petri dish is 50,000 (on day 0) if the amount is doubling each day by when will the number of bacter
Drupady [299]

Answer:

  • f(x) = 50000*2^x
  • 3 days

Step-by-step explanation:

<u>Given:</u>

  • Initial amount of bacteria = 50000
  • Growth rate = 2 times a day

<u>Required equation:</u>

  • f(x) = 50000*2^x

<u>Solve for x:</u>

  • 400000 = 50000*2^x
  • 2^x = 400000/50000
  • 2^x = 8
  • 2^x = 2^3
  • x = 3

After 3 days bacteria numbers will reach 400000

5 0
3 years ago
What is the solution to the equation 1/4x +2= -5/8x - 5
nalin [4]

Answer:

x = -8

Step-by-step explanation:

1/4x +2= -5/8x - 5

Add 5/8x to each side

1/4x +5/8x +2= -5/8x+5/8x - 5

1/4x+5/8x +2=  - 5

Subtract 2 from each side

1/4x+5/8x +2-2=  - 5-2

1/4x+5/8x =  - 7

Get a common denominator

1/4 *2/2 x + 5/8x = -7

2/8x + 5/8x = -7

7/8x = -7

Multiply each side by 8/7

8/7x * 7/8x = -7 *8/7

x = -8

7 0
3 years ago
Read 2 more answers
Newton's first law of motion applies only to objects that are already moving.<br> O True<br> O False
larisa [96]

Answer:

false

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
Factor 140c + 28 - 14a to identify the equivalent expressions.
Feliz [49]

Answer:

The answer to your question are letters A, C and D.

Step-by-step explanation:

To factor this polynomial we need to look for the common factor of the three terms.

To find it, get the greatest common factor

                        140    28   14     2

                          70    14     7     2

                          35     7     7     5

                            7     7      7     7

                             1     1       1    

Greatest common factor = 2 x 7 = 14  

Factor the polynomial

140c + 28 - 14a = 14 ( 10c + 2 - a)

Factor only 7          7(20c + 4 - 2a)

Factor only 2          2 (70c + 14 - 7a)

8 0
3 years ago
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