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Ivanshal [37]
4 years ago
15

Find the equation of a line parallel to y=−2x+4 that contains the point (−2,−5). Write the equation in slope-intercept form.

Mathematics
1 answer:
shtirl [24]4 years ago
3 0
Y=-2x-9, because the slope needs stay the same to be parallel and -2x-2 is 4 so to get -5 you have to subtract 9 from 4
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The measure of ∠E will be equal to 38°.

Given,

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∠AFB + ∠BFE = 180°

=> ∠AFB + 118° = 180°

=> ∠AFB = 62°

Now, we can see that ∠AFB and ∠FBD are equal because they are alternate angles.

And ∠FBD and ∠ABF are equal because BF bisects ∠ABD.

So, In ∆ABF,

∠AFB + ∠ABF + ∠BAF = 180° (because of the angle sum property of a triangle)

=>62° + 62° + ∠BAF = 180°

=>∠BAF = 180° - 124°

=> ∠BAF = 56°

Similarly, in ∆ABE,

∠A +∠C  +∠E = 180°

=> 56° + 86° + ∠E = 180°

=> ∠E = 38°

Therefore, m∠E = 38°.

Learn more about Angles of Triangle at

brainly.com/question/28736528

8 0
1 year ago
Give an example of fractions you wold compare by finding common numerators. Please help!
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The length of a rectangle is 5 m longer than its width. If the perimeter of the rectangle is 46 m , find its area.
lys-0071 [83]
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The perimeter, as we know, is equal to the sum of all sides. We have two “length” sides and two “width” sides, so our equation is:

x + x + x+5 + x+5 = 46
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x = 36/4
x = 9

So our width is 9m and the length is 14m.

The area of a rectangle is width times length, so:
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3 0
3 years ago
A librarian choose seven holiday books from a selection of ten to be displayed in the window of the library. in how many differe
Sergeu [11.5K]

Answer:

_{10}C_7=\frac{10!}{7!(10-7)!}\\\\=\frac{10!}{7!3!}=\frac{10\times 9\times 8\times ...}{(7\times 6\times 5\times...)(3\times 2\times 1)}\\\\=\frac{10\times 9\times 8}{3\times 2\times 1}=\frac{720}{6}=120

Step-by-step explanation:

A librarian choose seven holiday books from a selection of ten to be displayed in the window of the library. in how many different ways can she chose seven books?

This is a combination of 10 objects chosen 7 at a time:

_{10}C_7=\frac{10!}{7!(10-7)!}\\\\=\frac{10!}{7!3!}=\frac{10\times 9\times 8\times ...}{(7\times 6\times 5\times...)(3\times 2\times 1)}\\\\=\frac{10\times 9\times 8}{3\times 2\times 1}=\frac{720}{6}=120

3 0
3 years ago
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