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4 years ago

What is 3/5+1/4 in simplest form

2 answers:

7 0

$\frac{3}{5} + \frac{1}{4} \\ 
 \\ \frac{3*4}{5*4}=\frac{12}{20} \\ 
 \\ \frac{1*5}{4*5}= \frac{5}{20} \\ 
 \\ \frac{12}{20} + \frac{5}{20}= \frac{17}{20} \\ 
 \\ Solution: \frac{17}{20}$

ahrayia [7]4 years ago

3 0

3/5 12/20

+ 1/ 4 5/20

__________

17/20 is the answer

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(1 point) A, P and D are n×n matrices. Check the true statements below: A. A is diagonalizable if and only if A has n eigenvalue

yarga [219]

Answer:

Following are the answers to this questions:

A) False.

B) False.

C) True.

D) True.

Step-by-step explanation:

In option A,

Let A is $3 \times 3$ diagonal matrices that is,

$\left[\begin{array}{ccc}0&1&0\\0&0&6\\0&0&0\end{array}\right]$

here $A^3$ = 0, In this A is the nilpotent matrix and A has three values that are equal to 0 but it is not a diagonalizable matrix.

In option B,

If $A =\left[\begin{array}{ccc}0&1\\0&0\end{array}\right]$ in given value A elements are 0 and 1 as a distinct eigen value, that's why A is diagonalizable but |A| =0 its means A is not invertible, that's why it is false.

In option C,

It is given that $A= PDP^{-1}$ where A~ D, which is A is similar to diagonal matrices, that's why it is true.

In option D,

It is given that A has eigen vector, which leases from $R^n$ . A has eigen vector and A is $n \times n$ matrix, the number of A eigen values = given vector of A, that's why it is correct.

8 0

3 years ago

What is the median? 5, 10, 8, 9, 9, 9 TYPE ONLY THE NUMERIC ANSWER

8_murik_8 [283]

Answer:

Step-by-step explanation:

5, 8, 9, 9, 9, 10

(9+9)/2=9

6 0

3 years ago

Read 2 more answers

7x^2 - 16x - 15 please help find the factored form

myrzilka [38]

Step-by-step explanation:

7x^×2-16x-15

14x^-16x-15

8 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

4 years ago

-3p+6p help simplify

GarryVolchara [31]

Step-by-step explanation:

-3p+6p is 3p

-3 + 6 = 3

So when you simplify the equation you get 3p

6 0

2 years ago