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Helga [31]
3 years ago
5

At the 2012 London Olympics, Michael Phelps won the gold medal in the men's 100-meter butterfly.

Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

The total time was 52.35

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Here 2.4,1.6, 3.2,0.3, 1.5 . a)Calculate the means . b)Each piece of data is increased by 10. Calculate the new mean. c) Each ne
vagabundo [1.1K]

Answer:

1.8 ; 11.8 ; 4.18

Step-by-step explanation:

Given the data:

X : 2.4,1.6, 3.2,0.3, 1.5

Mean, m = Σx / n

Σx = 9 ; n = 5

m = 9 /5

m = 1.8

If data is increased by 10:

X : 12.4, 11.6, 13.2, 10.3, 11.5

Σx = 59 ; n = 5

m = 59 /5

m = 11.8

If data values is doubled :

X : 5.76, 2.56, 10.24, 0.09, 2.25

Σx = 20.9 ; n = 5

m = 20.9 /5

m = 4.18

7 0
3 years ago
What is the value of yearly compensation package that includes $65,000 salary the forecast of a $350 Dollar per month health ins
Klio2033 [76]

Answer:

$69560

Step-by-step explanation:

The yearly compensation package includes a yearly salary of $65000, the health insurance plan of $350 per month and a life insurance premium of $30 per month.

Total compensation in health insurance plan is $(350 × 12) = $4200

Total compensation in life insurance premium is $(30 × 12) = $360

Therefore, total yearly compensation package is $(65000 + 4200 + 360) = $69560 (Answer)

4 0
3 years ago
Cindi deposited $300 at 7.5% simple interest rate. How much interest will she earn after 5 years?
pav-90 [236]

Answer:

$431

Step-by-step explanation:

using the formula P(1+r/100)^n,

we can substitute the P with $300,

substitute the r with 7.5%,

and substitute the n with 5.

8 0
2 years ago
Please answer a few questions. :)
hichkok12 [17]
Sorry I can't read it,
 otherwise i would be happy to help you

8 0
3 years ago
Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(
Mumz [18]
The given equations are
x(t+1)-4t \sqrt{x} =9            (1)
2y+4y^{3/2}=t^{3}+t           (2)

When t=0, obtain
x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means \frac{dx}{dt}.

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1 
y'(0) = 1/2.
Here, y' means \frac{dy}{dt}.

Because \frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}, obtain
\frac{dy}{dx} |_{t=0}\, =  \frac{1/2}{3}= \frac{1}{6}

Answer:
The slope of the curve at t=0 is 1/6.



3 0
3 years ago
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