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photoshop1234 [79]
3 years ago
8

What is the nth derivative of sin^3x?

Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0
Using the chain rule.

<span><span>sin^3</span>(x) = [sin(x)<span>]^3

</span></span><span><span>d/<span>dx</span></span>[sin(x)<span>]^3</span>∗<span>d/<span>dx</span></span>[sin(x)]

</span>d/dx sinx = cosx 
d/dx<span> cosx = -sinx </span>
d/dx<span> (-sinx) = -cosx </span>
d/dx <span>(-cosx) = sinx
back to where we started from!!! </span>
So,
repeat repeat repeat !!
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