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3 years ago

Prefixes, roots, and suffixes are examples of _____

Mathematics

2 answers:

mojhsa [17]3 years ago

8 0

Answer:

The correct answer should be : Word parts

Step-by-step explanation:

DIA [1.3K]3 years ago

3 0

Word parts, none of the others make sense

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A - 7 x 2 for a = 15

marysya [2.9K]

Answer:

a- 7 x 2 is a = 14

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3 years ago

How do you do the area and how to do it to the nearest tenth

lord [1]

You just put I line in the middle and you times high times base the do the other one then add your answers up that should be your finely answer

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3 years ago

scores on a test have a mean of 67 and a standard devation of 10. michelle has a score of 87. convert michelle score to a z-scor

klasskru [66]

Answer:

z-score = 2.

Step-by-step explanation:

The z-score = (x - m) / d where x =the person's score, m = the mean and d = the standard deviation.

So we have (87-67)/10

= 2.

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3 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

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4 years ago

Eric has an estimated income of $2,270 per month. After budgeting his expenses he has found that he has about $836 remaining. If

vladimir1956 [14]

1,434÷2,270=0.63×100=63%

5 0

4 years ago