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erik [133]
3 years ago
7

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

more cans than Shane did. Write an inequality to determine the number of cans, S, that Shane could have collected. What is the solution set of the inequality? Also, What is the solution set of the inequality?
Mathematics
1 answer:
dangina [55]3 years ago
6 0

Answer:

2S+178\ge 2,000,

[911,\infty).

Step-by-step explanation:

Let S be the number of cans that Shane had collected.

Abha had collected 178 more cans than Shane did, then Abha had collected S+178 cans.

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling, this means that

S+S+178\ge 2,000,\\ \\2S+178\ge 2,000.

Solve this inequality:

1. Divide it by 2:

S+89\ge 1,000.

2. Now

S\ge 1,000-89,\\ \\S\ge 911.

The solution set is [911,\infty).

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See explanations below.

Step-by-step explanation:

12. If H(x) represent the percent of U.S households with internet use in x years after 1980 then;

a) H(23)=55 means the number of U.S households with internet use in 23 years after 1980 is 55

b)H(4)=k

so if in 23 years H, is 55, find in 1 year

In 1 year H= 55/23=k

c)H(27) ≥ 61 means in 27 years the number of U.S households with Internet use will be greater or equal to 61 households. If you check the results, in 27 years, H is 55/23 * 27 =64.5 ≅65 households which is at most 61 households.

d) H(17) + H(21)=H(29) means the sum of households with internet use  in 17 years and 21 years after 1980 equal the number of households with internet use in 29 years.Checking the results;

H(17) = 55/23 *17 =40.65

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H(17)+H(21)=40.65+50.22=90.87≅91 households

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13.

h(x)=-7x ; h(x)=63  ⇒replacing x in the second function with -7x

-7x=63

x=63/-7

x=-9

14.

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14.

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15.

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6x-12=18

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16. q(x) =1/2x -3 , q (x) =-4

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j(x)= -4/5 x + 7 ; j(x)= -5

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Learn More

Functions ; brainly.com/question/2316114

Keywords : Functions

#Learnwithbrainly

3 0
3 years ago
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Use the Pythagorean theorem...
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Answer:

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