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Nezavi [6.7K]
3 years ago
9

The extremes in the proportion 3/4=15/20 are

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

<span>In the form of a/b = c/d in proportions in math, the outer terms are called the extremes and the inner terms are called means. In the given 3/4 = 15/20, the outer terms or the extremes are 3 and 20.</span>

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5 is subtracted from one-fourth part of the product of 12 and 3 and multiplied by 2.​
elena-14-01-66 [18.8K]

Step-by-step explanation:

<h3>One fourth Part of Product of 12 and 3 </h3>

<h3>: 36 = 1/4 = 9</h3><h3>5 subtract from this = 9 - 5 = 4</h3>

<h3>Multiply by 2 = 2×4 = 8</h3>
3 0
3 years ago
Find the value of this expression if x= -6 and y=1. xy^2/-7
Ahat [919]
(-6)(1)∧⁽2/-7⁾= -6 is the answer
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8 0
3 years ago
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HELP! 8TH GRADE MATH PLS LOL
LekaFEV [45]
<h2><u>Given</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{x =  - 8}}}

<h2><u>Solution</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  = 3 \times  - 8 + 34}}}

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  =  - 24 + 34}}}

{ \large{ \bf{ ➢ \:  \: \cancel{2}y = 3 \times { \cancel{(10)} {} \:  \:  ^{5} }}}}

{ \large{ \therefore{  \bf{y = 15 \:  \: Ans.}}}}

3 0
3 years ago
A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found
irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

H_0: p = 0.04

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

H_a: p > 0.04

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that \mu = 0.04, \sigma = \sqrt{0.04*0.96}

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that n = 20, X = 0.1

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}

z = 1.37

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

7 0
3 years ago
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Lorico [155]
The given equality hold true when x = 2.

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For x = 4 and 6, L.H.S(2x+3) is greater than 7.

Hence for x = 2, 4 and 6, the above inequality holds true.

Hope this helps!
3 0
3 years ago
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