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2 years ago

The yearbook staff enlarges a picture with a length of 5 inches and a width of 7

Mathematics

2 answers:

Pepsi [2]2 years ago

6 0

present dimensions = 5*7

dimensions after scaling with factor 3 = 15*21

dimensions after reducing by scale factor 0.5 = 7.5*10.5

area of rectangle = length * breadth

so area of yearbook = 7.5*10.5 = 78.75

because, 78.75<80

so, the yearbook will fit in area of 80 inches^2

lapo4ka [179]2 years ago

5 0

I believe yes, the area of the picture is 78.75 square inches. hope this helps you

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9. A scale model of a building is 9 inches high. The scale is 1 inch = 2 feet. How tall would the building be?

frutty [35]

Answer:

18 Feet

Step-by-step explanation:

For every 1 inch, the building is 2 feet

There are 9 inches in the building

The equation would be 9 * 2 = 18

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2 years ago

Kelly skated 4 laps in 86 seconds. Which of the following is an equivalent rate of skating?

ikadub [295]

Answer:

D: 10 laps in 215 seconds

Step-by-step explanation:

86/4 = 21.5 seconds per lap

I went through and multiplied each lap number by the time per lap and the last one, D is the right answer!

Have an amazing day!

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2 years ago

2x+3y=-12 2x+t=-16 X=. Y= Help plz

8090 [49]

To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.

Answer:

x = -9

y = 2

Step-by-step explanation:

Solve the system:

2x + 3y = -12 [1]

2x + y = -16 [2]

Subtracting [1] and [2]:

3y - y = -12 + 16

2y = 4

y = 4/2 = 2

From [1]:

2x + 3(2) = -12

2x + 6 = -12

2x = -18

x = -18/2 = -9

Solution:

x = -9

y = 2

8 0

2 years ago

I get

dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

$g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2$

For absolute minimum we take the minimum values of $x$ and $y$ .

$x_{minimum} =1\\y_{minimum}=1\\$

Plugging in the minimum values in the function.

$g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\$

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of $x$ and $y$ .

$x_{maximum} =2\\y_{maximum}=2\\$

Plugging in the maximum values in the function.

$g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\$

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

3 0

3 years ago

Determine the intercepts of the line. y = 5 x − 1 3 y=5x−13

sweet-ann [11.9K]

Y-intercept = -13
x-intercept = 2.6 or 2 3/5
-13 is the y-intercept. In the equation, y=mx+b, b is the y-intercept. Looking at the equation, y=5x-13, we can see that -13 is in the place of b, therefore -13 is the y-intercept.
() is the x-intercept. To find the x-intercept, you need to replace values into the equation. Since the coordinates for the x-intercept consist of y being 0, you must replace y in the equation. with 0.
0=5x-13
Get rid of the -13 by adding it onto both sides. -13 is negative and the opposite of a negative is positive, thus making you add to get rid of -13.
0=5x-13
+13 +13
13=5x
Now you divide 5 from both sides to get rid of 5. The opposite of multiplication is division, so you must divide the 5 from 5x to isolate the x.
13/5=5x/5
2.6 or 2 3/5=x
Therefore the coordinates (2.6,0) represent the x-intercept, or just 2.6.

I hope this helped.

6 0

2 years ago