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Alika [10]
3 years ago
6

What is the LCM of 6, 17 and 34

Mathematics
2 answers:
In-s [12.5K]3 years ago
6 0

Answer:

102

Step-by-step explanation:

abruzzese [7]3 years ago
4 0

Answer:

It's 102

Glad to help! Your welcome.

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Suppose y varies directly with x. Write a direct variation equation that relates x and y. y=7 1/2 when x=3
kolbaska11 [484]

Answer:

y/x = 2.5

Step-by-step explanation:

y ∝ x

change ∝ to = by adding constant k or c

y = kx

Divide both sides by x

y/x = k, also k = y/x

Input the values

k = (7 1/2)/3.  Change 7 1/2 to improper fraction to give 15/2

k = (15/2)/3

k = \frac{15}{2} ÷ 3  

Change the division sign to multiplication which will change 3 to its inverse(1/3)

k = \frac{15}{2} × \frac{1}{3}

k = \frac{15}{6}

Divide the numerator and denominator by 3 to get 5/2

k = 5/2

From y/x = k,input k into the eqn

y/x = 5/2

y/x = 2.5

8 0
3 years ago
Show correct answers only!! i need asap!!
SOVA2 [1]

Answer:

11 1/2 aka D

Step-by-step explanation:

add 7 and 4 which is 11, then add 1/4 and 1/4 which is 1/2

4 0
3 years ago
Read 2 more answers
Find the slope of a line perpendicular to 2x-y-16
Alekssandra [29.7K]

put the equation 2x - y = 16 in the form of y = mx + c

2x - y = 16

2x = 16 + y

y = 2x - 16

the slope of this line is 2. the slope of a line perpendicular to it would be the negative reciprocal of 2. in other words, it would multiply with 2 to give -1.

you can form this equation with that info

2x = -1

x = -1/2

OR

you can flip and change the sign (numerator) of 2/1

2/1

= -1/2

6 0
3 years ago
ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
3 years ago
Y=20+6x <br> x=150-4x<br> Solve with equal values method
katen-ka-za [31]

Step-by-step explanation:

Identify the method that will be used to solve for x for each equation.

4x=20 division property  fo equality

x-11=9 addition property of eqaulity

5x+6x=22 Combining Like terms

5(x-2)=30 distibute property

HOPE THIS HELPS!!!!!!!!

//////////////////////////////////////////////////////////////////////////////////////////////////////////////

4 0
3 years ago
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