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3 years ago

Rewrite this decimal fraction as a decimal number.

Mathematics

2 answers:

Charra [1.4K]3 years ago

8 0

Answer:

14.25

Step-by-step explanation:

14 25/100= 14*100+25/100=

1400+25/ 100

= 1425/100

= 14.25

Afina-wow [57]3 years ago

5 0

Answer:

14.25

Step-by-step explanation:

the expression 14 25/100 can be written as 14+25/100

now converting 25 into decimal to cancel out the denominator we ll get 0.25

now adding 14 into 0.25

14+0.25

we get 14.25

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The sum of a 3 digit number and a 1 diget number is 217

muminat

216+1=217 or 215+2=217 ect.

8 0

3 years ago

Convert the following systems of equations to an augmented matrix and use Gauss-Jordan reduction to convert to an equilivalent m

Rasek [7]

Answer:

System of equations:

$x_1+2x_2+2x_3=6\\2x_1+x_2+x_3=6\\x_1+x_2+3x_3=6$

Augmented matrix:

$\left[\begin{array}{cccc}1&2&2&6\\2&1&1&6\\1&1&3&6\end{array}\right]$

Reduced Row Echelon matrix:

$\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&1&1\end{array}\right]$

Step-by-step explanation:

Convert the system into an augmented matrix:

$\left[\begin{array}{cccc}1&2&2&6\\2&1&1&6\\1&1&3&6\end{array}\right]$

For notation, R_n is the new nth row and r_n the unchanged one.

1. Operations:

$R_2=-2r_1+r_2\\R_3=-r_1+r_3$

Resulting matrix:

$\left[\begin{array}{cccc}1&2&2&6\\0&-3&-3&-6\\0&-1&1&0\end{array}\right]$

2. Operations:

$R_2=-\frac{1}{3}r_2$

Resulting matrix:

$\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&-1&1&0\end{array}\right]$

3. Operations:

$R_3=r_2+r_3$

Resulting matrix:

$\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&2&2\end{array}\right]$

4. Operations:

$R_3=\frac{1}{2}r_3$

Resulting matrix:

$\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&1&1\end{array}\right]$

4 0

4 years ago

70. Write the standard form of the equation of the line with

nasty-shy [4]

Answer:

y = -2x - 8

Step-by-step explanation:

Use the point slope form: (y - y1) = m(x - x1)

(y - (-4)) = -2(x - (-2))

y + 4 = -2(x + 2)

y + 4 - 4 = -2x - 4 - 4

y = -2x - 8

Answer: y = -2x - 8

6 0

3 years ago

Read 2 more answers

Find (ƒ – g)(x) where ƒ(x) = 2x2 + 5x – 8, g(x) = –x2 + 6x.

STatiana [176]

Answer:

Step-by-step explanation:

ƒ(x) = 2x2 + 5x – 8

g(x) = –x2 + 6x

(ƒ – g)(x)=2x2+5x-8-(-x2+6x)

=2x2+5x-8+x2-6x

=3x2-x-8

6 0

3 years ago

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

QUESTION 1

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

QUESTION 2

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

QUESTION 3

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

4 years ago

Read 2 more answers