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2 years ago

1/2(y+3)>1/3(4-y) with the steps

Mathematics

1 answer:

lys-0071 [83]2 years ago

3 0

$\frac{1}{2(y-3)}>\frac{1}{3(4-y)}=>3(4-y)>2(y-3)$

12 - 3y > 2y - 6

12 + 6 > 2y + 3y

18 > 5y

$y$

y ∈ (-oo, $\frac{5}{18}$ )

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If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago

If −5e^x^2 y=x and y(−5)=0, find y′(−5) by implicit differentiation

xenn [34]

Differentiate:
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When x=-5, y=0:
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Step-by-step explanation:

Multiply straight across the numerator and do the same for the denominator.

7x1=7 (numerator)

16x2=32 (denominator)

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