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mafiozo [28]
3 years ago
14

I don't know how to do questions 3 or 4 need help please!!

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0
3 is 11° and 4 is 81.4"
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Suppose we select, without looking, one marbles from a bag containing 4 red marbles and 10 green marbles.what is the probability
OlgaM077 [116]
Since 10 out of 14 marbles are green, the probability of selecting a green marble is 10/14=0.714.

Similarly, the probability of selecting a red marble would be 4/14.

Answer: 0.714


5 0
2 years ago
Expand the expression.<br> -7(k - 3)<br> -7k + 21<br> -k – 21<br> k+ 21<br> -7k - 21
garri49 [273]

Answer:

-43K+42

Step-by-step explanation:

3 0
3 years ago
Question on picture. Please help
Elden [556K]
A rhombus is quadrilateral where all 4 sides are of equal length. Thus


5x + 2 = 2x + 12

3x = 10

x = 10/3

substituting x into either expression, yields

56/3

therefore side AB = 56/3


3 0
3 years ago
From the top of a 100-ft building a man
romanna [79]

Answer:

219m

Step-by-step explanation:

Since the man observes the car with angle 15 before observing in 33 degrees.

For the first observation

The angle observation gives an angle if 33 degrees with the horizontal.

It gives a triangle which I'll attach to the que,

from the first triangle

Tan 33 = 100/y

Y= 100/ tan 33

Y = 153.99m.

This is the distance from the building to the distance where it was secondly observed( 33).

To find x

tan 15 = 100/(153.99+x)

153.99 + x = 100/ tan 15

153.99 + x = 373.21

The distance between the two observed angles

X= 219m.

5 0
3 years ago
Test the hypothesis using the P value approach. Be sure the verify the requirements of the test.
Andreas93 [3]

Answer:

p_v =2*P(z  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly different from 0.77.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X=380 represent the number of people with some characteristic

\hat p=\frac{380}{500}=0.76 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.76 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.7 .:  

Null hypothesis:p=0.77  

Alternative hypothesis:p \neq 0.77  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np_o =500*0.77=385>10

n(1-p_o)=384*(1-0.77)=115>10

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.76-0.77}{\sqrt{\frac{0.77(1-0.77)}{500}}}=-0.531  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly different from 0.77.  

6 0
3 years ago
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