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3 years ago

Please help me solve this problem, and someone please clearly explain to me how to solve it.

Mathematics

1 answer:

allsm [11]3 years ago

6 0

Step-by-step explanation:

For a trinomial ax² + bx + c = 0, the discriminant is b² − 4ac.

If the discriminant is positive, there are 2 real solutions.

If the discriminant is 0, there is 1 real solution.

If the discriminant is negative, there are no real solutions.

a) x² − 4x − 7 = 0

Here, a = 1, b = -4, and c = -7.

b² − 4ac = (-4)² − 4(1)(-7) = 44

The discriminant is positive, so there are 2 real solutions.

b) 4r² + 11r − 3 = 0

Here, a = 4, b = 11, and c = -3.

b² − 4ac = (4)² − 4(11)(-3) = 148

The discriminant is positive, so there are 2 real solutions.

c) 3m² + 7 = 0

Here, a = 3, b = 0, and c = 7.

b² − 4ac = (0)² − 4(3)(7) = -84

The discriminant is negative, so there are no real solutions.

d) t² + 2t + 1 = 0

Here, a = 1, b = 2, and c = 1.

b² − 4ac = (2)² − 4(1)(1) = 0

The discriminant is zero, so there is 1 real solution.

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After 4 months of living in her dorm room, Molly had 5 fish. Eight months later, Molly still had 5 fish. Which of the graphs bel

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We can assume the x value is time, and the y-value is fish population.

The best answer is the third option, a line going through 0,5 and 7,5. We don't know if Molly arrived at the dorm with fish, but we know that during the 8 months, her fish population stayed the same at 5 fish.

The first option features a y value of 8, so we know that's wrong. She never had more than 5 fish.
The second option is wrong for the same reason (y values of 6 and 9)
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4 years ago

Can someone please help me with these questions?

nikitadnepr [17]

QUESTION 1

The given function is

$y = - 6x - 13$

The domain of this function refers to all values of x for which y is defined.

The given function is defined for all real values of x.

The domain is all real numbers.

The correct answer is A

QUESTION 2

The equation in column 1 is

$y = - 2 {x}^{2} - 4x + 12$

We obtain the vertex form as follows;

$y = - 2( {x}^{2} + 2x) + 12$

$y = - 2( {x}^{2} + 2x + {1}^{2}) - - 2 {(1)}^{2} + 12$

$y = - 2({(x + 1)}^{2}) + 2 + 12$

$y = - 2({x + 1)}^{2} + 14$

The x-value of the vertex is -1.

The equation in column 2 is

$y = {x}^{2} - 4x + 3$

We can also find the x-value of the vertex using the formula,

$x = - \frac{b}{2a}$

$x = - \frac{ - 4}{2(1)}$

$x = 2$
The correct answer is

B) The value found in column #1 is less than the value found in column #2

QUESTION 3

The height of the ball is modeled by

$h(t) = - 16 {t}^{2} + 64t$
where t equals the time in seconds and h(t) represents the height of the ball at time t seconds.

The axis of symmetry can be found using the formula,

$t = - \frac{b}{2a}$

$t = - \frac{ 64}{2( - 16)}$

$t = 2$

The correct answer is

A) t=2; it takes 2 seconds to reach maximum height and 2 seconds to fall back to the ground

QUESTION 4

The equation of axis of symmetry is given by the formula,

$x = - \frac{b}{2a}$

For the axis of symmetry of a given quadratic function to be zero, then the b-value of quadratic function should be zero.

The only equation from the given options whose b-value is zero is

$y = {x}^{2} + 2$

The axis of symmetry is

$x = - \frac{0}{2(1)}$

$x = 0$

The correct answer is C

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3 years ago

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Answer:

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3 years ago

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