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Sergeeva-Olga [200]
3 years ago
11

Given that y varies inversely with x, if x =7 and y = 4, what is y when x = 2?

Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

y=14

Step-by-step explanation:

y \propto 1/x

y=k/x

4=k/7

4 \times 7 = k

28=k

y=28/x

y=28/(2)

y=14

AysviL [449]3 years ago
3 0

Answer:

y = 14

Step-by-step explanation:

y ∝ \frac{1}{x}

=> y = \frac{k}{x}     -------------(1)

<em><u>Where k is the constant of proportionality</u></em>

Now,

x = 7, y = 4

<em>Putting in (1)</em>

4 = \frac{k}{7}

So,

=> k = 28

Now y = ? when x = 2

<em>Putting x and k in (i)</em>

y = \frac{28}{2}

y = 14

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You might have made an error the first time you solved for x. I got x = -0.5.

When you have your log base 4, the way you cancel that out is by making 4 the base on both sides, so you get 4^(log4) to reduce to 1, and you're left with:

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Find x, y and ab and how to check if the answer is right ​
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Answer:

  x = 2, y = -2, AB = 142

Step-by-step explanation:

The fact that X is the midpoint gives you two relations:

  AX = XB

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  24x +40 -3y +21 -22x = 5x +y +23 -4x +48

  2x -3y +61 = x +y +71 . . . . . . we can use this simplification

  x -4y = 10 . . . . . . . . . . . . . . . . subtract x+y+61

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