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2 years ago

Given that y varies inversely with x, if x =7 and y = 4, what is y when x = 2?

Mathematics

2 answers:

jeyben [28]2 years ago

7 0

Answer:

$y=14$

Step-by-step explanation:

$y \propto 1/x$

$y=k/x$

$4=k/7$

$4 \times 7 = k$

$28=k$

$y=28/x$

$y=28/(2)$

$y=14$

AysviL [449]2 years ago

3 0

Answer:

y = 14

Step-by-step explanation:

y ∝ $\frac{1}{x}$

=> y = $\frac{k}{x}$ -------------(1)

Where k is the constant of proportionality

Now,

x = 7, y = 4

Putting in (1)

4 = $\frac{k}{7}$

So,

=> k = 28

Now y = ? when x = 2

Putting x and k in (i)

y = $\frac{28}{2}$

y = 14

You might be interested in

Find the m of

zzz [600]

Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.

[23] ABD = 42°, DBC = 35°

(4x - 2) + (3x + 2) = 77°

4x+ 3x + 2 - 2 = 77°

4x+ 3x= 77°

7x= 77°

x= 11°

ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°

DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°

[24] ABD = 62°, DBC = 78°

(4x - 8) + (4x + 8) = 140°

4x + 4x + 8 - 8 = 140°

4x + 4x = 140°

8x = 140°

x = 17.5°

ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°

DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°

6 0

1 year ago

A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust

AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let X = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts n = 8 potential customers per day.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...$

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

$P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488$

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

= 1 - P (X = 0) - P (X = 1)

$=1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869$

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

$P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305$

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

$E(X)=np=8\times 0.10=0.80$

Thus, the expected number of sales per day is 0.80.

7 0

2 years ago

Help on A and B please

weqwewe [10]

Answer:

b bbbbbbbbbbb

3 0

2 years ago

Answer all of the questions below in order to determine the volume of the rectangular prism. 10 3 5 Press the play button: play

soldier1979 [14.2K]

Answer:

10, 50, 150

Step-by-step explanation:

i just did it lol.

7 0

2 years ago

1.4t-0.4(t-3.1)=5.8 please help !!

Svetllana [295]

Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56

4 0

3 years ago