The volume of the car is 1800cm^3 which is equivalent to 0.0018m^3
<h3>Scale modelling</h3>
Given the scale factor that model of a car is amde to a scale of 1:40, Giving that the model as 45cm^3, this means that;
1 = 45cm^2
Determine the volume of the car
40 = x
Find the ratio
1/40 = 45/x
x = 40*45
x = 1800cm^3
x = 0.0018m^3
Hence the volume of the car is 1800cm^3 which is equivalent to 0.0018m^3
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Answer:
The equation is y = 2x + 11.
Step-by-step explanation:
It is given that the gradient of the equation is 2. Using slope-form formula, y = mx+b where m is gradient and b is y-intercept. In order to find b, you have to substitute x-coordinate and y-coordinate into the equation :
y = mx + b
m = 2
At(-4,3),
3 = 2(-4) + b
b = 3 - 2(-4)
= 11
Yes, the sampling distribution is normally distributed because the population is normally distributed.
A sampling distribution is a chance distribution of a statistic obtained from a larger variety of samples drawn from a specific populace. The sampling distribution of a given population is the distribution of frequencies of a variety of various outcomes that would probable occur for a statistic of a populace.
A sampling distribution is a probability distribution of a statistic this is obtained via drawing a huge variety of samples from a particular populace. Researchers use sampling distributions so that you can simplify the technique of statistical inference.
Solution :
mean = μ40
standard deviation σ σ= 3
n = 10
μx = 40
σ x = σ√n = 3/√10 = 0.9487
μ x = 4σ\x = 0.9487
σx = 0.9487
Yes, the sampling distribution is normally distributed because the population is normally distributed.
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Answer:
The correct option is;
False
Step-by-step explanation:
The coefficient of x^k·y^(n-k) is nk, False
The kth coefficient of the binomial expansion, (x + y)ⁿ is 
Where;
k = r - 1
r = The term in the series
For an example the expansion of (x + y)⁵, we have;
(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵
The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15
Therefore, the coefficient of x^k·y^(n-k) for the expansion (x + y)ⁿ = 
not nk
