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Stolb23 [73]
3 years ago
11

Figure out the answer to each riddle below:

Mathematics
1 answer:
Ahat [919]3 years ago
5 0
1. 79
2. 330
3. 452
4. 1212
5. 351
6. 202
7. 238
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Answer: Shelly will need 6 cups of sugar.

Step-by-step explanation:

Multiply 3 by 1/2

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A spinner with 12 equal sections is spun. Each section is numbered 1 to 12. What Is the probability of landing on an odd number.
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Please help!!!!!!solve
fgiga [73]
I’m a bit confused confused, but the answer may be -2x^3 + 2x^2 - 2x +2

Work:

To solve this, take the equation for q and the equation for r, and multiply them together.

Use the distributive property to multiply them.

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3 years ago
3w-4z=8<br> 2w+3z=-6 solve
marissa [1.9K]

Answer:

W = 0

Z = -2

Step-by-step explanation:

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4 0
3 years ago
A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u
OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

\displaystyle\frac{8000\pi\sqrt{2}}{3}

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

x^2+y^2=15^2\to y=\sqrt{225-x^2}

Then we set the integral for the volume by using shell method:

\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx

That can be solved by substitution:

u=225-x^2\to du=-2xdx

The limits of integration also change:

For x=5: u=225-5^2=200

For x=15: u=225-15^2=0

So the integral becomes:

\displaystyle -\int_{200}^{0}\pi \sqrt{u}du

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

\displaystyle \int_{0}^{200}\pi u^{1/2}du

Then applying the basic rule we get:

\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}

Since that is just half of the solid, we multiply by 2 to get the complete volume:

\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}

=\displaystyle\frac{8000\pi\sqrt{2}}{3}

5 0
3 years ago
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