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Damm [24]
3 years ago
8

Question 4) e) and f) please Tonks

Mathematics
2 answers:
melisa1 [442]3 years ago
7 0
E) (x-2)(x-1)
substitute x = 0
 = (0-2)(0-1)
 = (-2)(-1)
 = 2

f)2x(3x+2)
Substitute x = 10
2*10(3(10)+2)
= 20(30+2)
= 20(32)
= 640

Hope this helps!
lora16 [44]3 years ago
4 0
I hope this helps you

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3 years ago
In the diagram below, OP is circumscribed about quadrilateral ABCD. What is
elena-s [515]

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My name is Ann [436]

Answer:

Quadratic expression

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6 0
3 years ago
Read 2 more answers
How do I factor this
melamori03 [73]
There is a factor of 10p in each term that is common, and thus, you can take them out of each term to yield 10p(p² - 196).
Now, 196 is a perfect square. That is, there is a real number that when multiplied by itself gives 196 (14).
Since p² - 14² is a difference of two squares, we can rewrite it as (p + 14)(p - 14).

So, our factored form is 10p(p + 14)(p - 14)
3 0
3 years ago
Can somebody help me please
AnnyKZ [126]

It's an isosceles triangle so angles A and BCA are congruent.  

Angle BCA is the supplement of BCD, so 180-109 = 71.

Angle A is congruent to that, so A=71 degrees.

Let's see if we can get that in the format they want, kind of as a proof.

1.  ∠BCD=109° Reason: Given

2. AB ≅ BC      Reason: Given

3. ∠BCA = 71°  Reason: Linear pairs are supplementary

4. ΔABC is isosceles.   Reason: Definition of isosceles

5. ∠A ≅ ∠BCA   Reason: Isoceles triangle theorem

6. ∠A = 71°         Reason: Def congruent

Answer: 71 degrees

5 0
3 years ago
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