1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nirvana33 [79]
3 years ago
7

Two person A and B of weight 60kg and 40kg respectively stand facing each other, and pull on a light rope streched between them.

Find the ratio of distance covered by them when they meet if their intial separation was 5 metre
Physics
1 answer:
goblinko [34]3 years ago
6 0

To be able to successfully pull the rope with balance, the work done by person A should be just equal to the work done by person B.

<span>workA = workB  ----> 1</span>

Where: work = force * distance

In this case, force = mass * gravity

So work = mass * gravity * distance

Rewriting equation 1:

<span>massA * gravity * distanceA = massB * gravity * distanceB  ---->2</span>

We know that distanceA + distanceB = 5 m, therefore distanceA = 5 – distanceB. Substituting this to equation 2 and cancelling constant g:

massA * distanceA = massB * distanceB

60 kg * (5 – distanceB) = 40 kg * distanceB

distanceB = 3 m

distanceA = 5 – distanceB = 2 m

 

<span>ratio is: distanceA / distanceB = 2/3 = 0.67</span>

You might be interested in
Multiple-Concept Example 6 reveiws the principles that play a role in this problem. A nuclear power reactor generates 2.3 x 109
r-ruslan [8.4K]

Answer:

change in mass = 2.41*10^{8}kg

Explanation:

The change in the mass can be computed by using the relation

E=\Delta mc^2\\\Delta m=\frac{E}{c^2}(1)

That is, the energy liberated comes from the mass of the nuclear fuel. The energy generated in one year is

E=Pt=2.3*10^{9}\frac{J}{s}*1 year*\frac{365.25 day}{1 year}*\frac{24h}{1 day}*\frac{3600s}{1h}=7.25*10^{16}J

Hence, by replacing in the equation (1) you have  (c=3*10^{8}m/s)

\Delta m=\frac{7.25*10^{16}J}{3*10^{8}\frac{m}{s}}=2.41*10^{8}kg

HOPE THIS HELPS!!

3 0
3 years ago
Read 2 more answers
A person must pull a rope 20 meters with a force of 200 N what is the work input?
tatiyna
Work done = force * distance
work done = 200 * 20
work done = 4000J
4 0
3 years ago
Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of
navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0
2 years ago
An astronaut on a strange new planet having no atmosphere finds that she can jump up to a maximum height of 27 m when her initia
vekshin1
The magnitude is 4.5
7 0
3 years ago
Read 2 more answers
Four point charges, each of magnitude 2.38 µC, are placed at the corners of a square 75.2 cm on a side. If three of the charges
poizon [28]

Answer:

The Electric Force on Negative Charge is 2.968 N

Explanation:

charge on each corner, q = 2.38 micro coulomb

Side of square, a = 75.2 cm

Coulombic constant, K = 8.98755 x 10^9 Nm²/C²

sides of the square are A,B,C and D

and all sides of a square are equal so

AB = BC = CD = DA = 75.2 cm = 0.752 m

Diagonal, AC = BD = 1.414 x 0.752 = 1.06 m

Electric field at D due to charge at A

EA= Kq÷AB^2

= 8.98755×10^9 × 9.87×10^-6 ÷ 0.752^2

EA= 156863.82 N/C

Similarly Electric field at D due to charge C

EC=Kq÷CD^2

= 8.98755×10^9 ×9.87×10^-6 ÷ 0.752^2

EC= 156863.82 N/C

Electric field at D due to charge at BB

EB=Kq÷BD^2

EB=8.98755×10^9 × 9.87×10^-6 ÷ 1.06^2

EB=78949.01 N/C

Resolve the compoents

Ex = EA + EB cos 45

Ex = 156863.82 + 78949.01 x 0.707

Ex = 212689.2 N/C

Ey = EC + EB Sin 45

Ey = 156863.82 + 78949.01 x 0.707

Ey = 212689.2 N/C

The resultant electric field is

E = 1.414 x 212689.2 = 300787.95 N/C

the electric force on the negative charge is

F = q x E

F = 9.87 x 10^-6 x 300787.95

F = 2.968 N

7 0
2 years ago
Other questions:
  • Which of the following does not use an internal combustion enginea. a cannonb. a lawnmowerc. a windmilld. a car
    12·2 answers
  • Need help asap ‼️ 20 pts
    11·1 answer
  • A car travels along a highway with a velocity of 24 m/s, west. The car exits the highway; and 4.0 s later, its instantaneous vel
    13·1 answer
  • Which best describes a value for density
    13·1 answer
  • Janet jumps off a high diving platform with a horizontal velocity of 2.8 meters per second in lands in the_________.
    15·1 answer
  • I need this fast can you help me o give 12 points
    13·2 answers
  • Helium does not usually react with other substances. does this mean that helium has no chemical reactions
    5·1 answer
  • PLEASE HELP
    13·1 answer
  • Question 1 of 25<br> In the covalent compound CO₂, the Greek prefix used to represent the anion is
    8·1 answer
  • If the coefficient of kinetic friction between tires and dry pavement is 0.93. What is the shortest distance in which you can st
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!