Fossil fuels like coal, natural gas and oil.
Hopes this helps!
Answer:
When you have a cloudy night, the clouds prevent heat from escaping through the atmosphere and into space.
The clouds act like a blanket and trap the heat it, and that is why every time you have a cloudy night, it is always warmer than a clear night.
Answer:
27.44 J
Explanation:
We can find the energy at the top of the slide by using the potential energy equation:
At the top of the slide, the swimmer has 0 kinetic energy and maximum potential energy.
The swimmer's mass is given as 7.00 kg.
The acceleration due to gravity is 9.8 m/s².
The (vertical) height of the water slide is 0.40 m.
Substitute these values into the potential energy equation:
- PE = (7.00)(9.8)(0.40)
- PE = 27.44
Since there is 0 kinetic energy at the top of the slide, the total energy present is the swimmer's potential energy.
Therefore, the answer is 27.44 J of energy when the swimmer is at the top of the slide.
Answer:
0.76 s
Explanation:
We are given that
Length of rod,L=20 cm=
1 m=100 cm
Mass of rod,M=190 g=
Mass of ball,m=19 g=
Using 1 kg=1000g
We have to find the period if the rod and clay swing as a pendulum.
Moment of inertia of rod-clay=Moment of inertia of rod+moment of inertia of clay


Substitute the values then we get


Now, the center of mass of the combination of the rod and clay is given by

Substitute
=Distance between pivot and the center of the rod
The distance between rod and clay
Using the formula

m
Time period of the oscillation of the system of the rod and the clay is given by

g=
Using the formula
Time period=
Time-period=0.76 s
Hence, the period =0.76 s