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RoseWind [281]
3 years ago
7

Blank can cause magma within Earth to blank resulting in the formation of blank rock

Physics
1 answer:
Lana71 [14]3 years ago
3 0

Answer:

Cooling can cause magma withing Earth to solidify resulting in the formation of igneous rocks

Explanation:

Magma consists of molten or semi-molten material that forms in the mantle and travels upward due to the presence of convective currents in the Earth's interior. As the magma travels upward, it encounters lower temperatures: as a result, its temperature cools down, and the material solidifies. The rocks that form as a result of this process are called igneous rocks. There are over 700 types of igneous rocks beneath the Earth's surface, and they are known to form (together with metamorphic rock) up to 90% of all rocks to a depth of 10-15 km from the surface.

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Answer:

about 2.7liters for women and 3.7liters for men

Explanation:

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Gravity on earth is 9.8 m/s squared, and gravity on the moon is 1.6 m/s squared. So if the mass of an object on earth is 40 kilo
garik1379 [7]

The mass of an object on Earth is the same as its mass on the Moon. The weight is different.

Weight = m * g

Weight ( Moon ) = 40 kg * 1.6 m/s² = 64 N

If the mass of an object on Earth is 40 kg, its mass on the Moon is 40 kg and its weight on the Moon is 64 N. 

7 0
3 years ago
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of
motikmotik

Explanation:

It is given that, the force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed such that,

F\propto \dfrac{mgv^2}{r}

F=\dfrac{kmgv^2}{r}

mg is the weight of the car

r is the radius of the curve

v is the speed of the car

Case 1.

F = 640 pounds

Weight of the car, W = mg = 2600 pound

Radius of the curve, r = 650 ft

Speed of the car, v = 40 mph

640=\dfrac{k(2600)(40)^2}{650}

k = 0.1

Case 2.

Radius of the curve, r = 750 ft

Speed of the car, v = 30 mph

F=\dfrac{0.1\times 2600\times (30)^2}{750}

F = 312 N

Hence, this is the required solution.

6 0
2 years ago
What is the pressure at the bottom of a tank 1-m deep? Take the density of water to be 1000-kg/m^3, and gravitational accelerati
lara31 [8.8K]

To solve this problem we will use the concepts related to hydrostatic pressure. Which determines the pressure of a body at a given depth of a liquid.

Mathematically this can be described as

P= \rho gh

Here

\rho = Density

g = Gravity

h = Height (Depth)

If we replace the values given in the equation we will have to

P = 1000 (9.8)(1)

P = 9800 Pa

Therefore the pressure at the bottom will be 9.8kPa

4 0
3 years ago
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