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4 years ago

5

Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?

2 answers:

kondaur [170]4 years ago

8 0

Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?

A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.

B) Strong electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.

C) Being a strong electrolyte refers the type of bonding and has no bearing on conducting electricity.

D) Strong electrolytes do not dissolve in water and can not conduct electricity.

ANSWER:

A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.

pishuonlain [190]4 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

When a compound dissolves in a solution and changes into ions then it is able to conduct electricity.

For example, KCl is an ionic compound and when dissolved in a solution then it is able to dissociate into $K^{+}$ and $Cl^{-}$ ions. Hence, it is able to conduct electricity.

Therefore, we can conclude that ionic solutes are considered strong electrolytes because strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.

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Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is th

katrin [286]

Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

Answer:

$F=2*10^{4}N$

Explanation:

From the question we are told that:

Mass $m=0.500kg$

Initial Velocity $V=15.0m/s$

Distance $x=2.80mm=>0.00280m$

Diameter $d=2.50mm=>0.00250m$

Length $l=6.00cm=>0.6m$

Generally the equation for Force is mathematically given by

$F=\frac{mv^2}{2d}$

$F=\frac{0.500*15^2}{2.80*10^{-3}}$

$F=2*10^{4}N$

6 0

3 years ago

A person standing a certain distance from four identical loudspeakers is hearing a sound level intensity of 125 dB. What sound l

DENIUS [597]

Answer:

$\mathbf{\beta = 123.75 \ dB}$

Explanation:

From the question, using the expression:

$125 \ dB = 10 \ log (\dfrac{I}{I_o})$

where;

$I_o = 10^{-12} \ W/m^2$

$I = 10^{12.5} \times 10^{-12} \ W/m^2$

$I = 3.162 \ W/m^2$

This is a combined intensity of 4 speakers.

Thus, the intensity of 3 speakers = $\dfrac{3.162\times 3}{4}$

= 2.372 W/m²

Thus;

$\beta = 10 \ log ( \dfrac{2.372}{10^{-12}} ) \ W/m^2$

$\mathbf{\beta = 123.75 \ dB}$

7 0

3 years ago

What is the heat extracted from the cold reservoir for the refrigerator?

zaharov [31]

What is the heat extracted from the cold reservoir for the refrigerator shown in(Figure 1) ? Assume that W1 = -123J and W2 = 88J .

<span>Qc= _________ </span>

<span>Part B
</span>
K=105J

7 0

3 years ago

When ___ attacks the surface of a metal, it becomes tarnished.

alexandr1967 [171]

Answer:corrosion (i believe)

Explanation:

6 0

3 years ago

Read 2 more answers

A 1.80-m string of weight 0.0126 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Neglect the v

Veseljchak [2.6K]

Answer:

W = 0.135 N

Explanation:

Given:

- y (x, t) = 8.50*cos(172*x -2730*t)

- Weight of string m*g = 0.0126 N

- Attached weight = W

Find:

The attached weight W given that Tension and W are equal.

Solution:

The general form of standing mechanical waves is given by:

y (x, t) = A*cos(k*x -w*t)

Where k = stiffness and w = angular frequency

Hence,

k = 172 and w = 2730

- Calculate wave speed V:

V = w / k = 2730 / 172 = 13.78 m/s

- Tension in the string T:

T = Y*V^2

where Y: is the mass per unit length of the string.

- The tension T and weight attached W are equal:

T = W = Y*V^2 = (w/L*g)*V^2

W = (0.0126 / 1.8*9.81)*(13.78)^2

W = 0.135 N

4 0

4 years ago