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iVinArrow [24]
3 years ago
5

Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?

Physics
2 answers:
kondaur [170]3 years ago
8 0

Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?  


A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.  

B) Strong electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.  

C) Being a strong electrolyte refers the type of bonding and has no bearing on conducting electricity.  

D) Strong electrolytes do not dissolve in water and can not conduct electricity.  

                                          ANSWER:

A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.


pishuonlain [190]3 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

When a compound dissolves in a solution and changes into ions then it is able to conduct electricity.

For example, KCl is an ionic compound and when dissolved in a solution then it is able to dissociate into K^{+} and Cl^{-} ions. Hence, it is able to conduct electricity.

Therefore, we can conclude that ionic solutes are considered strong electrolytes because strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.

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3 years ago
Parallel to the handle, what is the force of friction acting on the suitcase?
mrs_skeptik [129]
 <span>Lets call F the friction force which will act horizontally backwards. 

As you are travelling at a constant velosity horizontally there is no overall resultant force in this direction. 

ie. the force you pull with will be equal to the friction force resisting you. (you will initially have to have pulled with a greater force than the friction to get the suitcase moving) 

the value of your force pulling is 60 cos26.9 (horizontally) - you should have learnt about resolving forces. 

this must be equal to F 

so 

F=60cos26.9 
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hope this helps you
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5 0
3 years ago
You are at the top of the Empire State Building on the 102nd floor, which is located 373 m above the ground, when your favorite
Liula [17]

Answer:

1.5 m

Explanation:

H = actual height of the superhero = ?

H₀ = height of the superhero as observed = 1.73 m

v = speed of the superhero = 0.50 c

Using the equation

H = H_{o} \sqrt{1 - \left ( \frac{v}{c} \right )^{2}}

Inserting the values

H = 1.73 \sqrt{1 - \left ( \frac{0.50 c}{c} \right )^{2}}

H = 1.5 m

3 0
3 years ago
The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o
LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

\bar F \cdot \Delta t = m \cdot  (v_{2}-v_{1}) (1)

Where:

\bar F - Average impact force, in newtons.

\Delta t - Duration of the impact, in seconds.

m - Mass of the sledge hammer, in kilograms.

v_{1}, v_{2} - Initial and final velocity, in meters per second.

If we know that \Delta t = 0.0020\,s, m = 4\,kg, v_{1} = -6\,\frac{m}{s} and v_{2} = 0\,\frac{m}{s}, then we estimate the average impact force is:

\bar F = \frac{m\cdot  (v_{2}-v_{1})}{\Delta t}

\bar F = 12000\,N

The average impact force is 12000 newtons.

5 0
3 years ago
P14.003A spherical gas-storage tank with an inside diameter of 8.1 m is being constructed to store gas under an internal pressur
Artist 52 [7]

Answer:

The minimum wall thickness required for the spherical tank is 0.0189 m

Explanation:

Given data:

d = inside diameter = 8.1 m

P = internal pressure = 1.26 MPa

σ = 270 MPa

factor of safety = 2

Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?

The allow factor of safety:

\sigma _{a}  =\frac{\sigma }{factor-of-safety} =\frac{270}{2} =135MPa

The minimun wall thickness:

t=\frac{Pd}{4\sigma _{a} } =\frac{1.26*8.1}{4*135} =0.0189m

3 0
3 years ago
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