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iVinArrow [24]
4 years ago
5

Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?

Physics
2 answers:
kondaur [170]4 years ago
8 0

Ionic solutes are considered strong electrolytes. What does this mean for the conductivity of the solution?  


A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.  

B) Strong electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.  

C) Being a strong electrolyte refers the type of bonding and has no bearing on conducting electricity.  

D) Strong electrolytes do not dissolve in water and can not conduct electricity.  

                                          ANSWER:

A) Strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.


pishuonlain [190]4 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

When a compound dissolves in a solution and changes into ions then it is able to conduct electricity.

For example, KCl is an ionic compound and when dissolved in a solution then it is able to dissociate into K^{+} and Cl^{-} ions. Hence, it is able to conduct electricity.

Therefore, we can conclude that ionic solutes are considered strong electrolytes because strong electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.

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Answer:

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C. it's still hot from the big bang

Explanation:

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  • Nuclear reactions within the earth interior by fusion and other radioactive processes releases a large amount of heat.
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3 years ago
A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s.
marishachu [46]

Answer:

a) the magnitude of the force is

F= Q(\frac{kqs}{r^3}) and where k = 1/4πε₀

F = Qqs/4πε₀r³

b)  the magnitude of the torque on the dipole

τ = Qqs/4πε₀r²

Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

where k = 1/4πε₀

the expression of the electric field due to dipole at a distance r is

E(r) = \frac{kp}{r^{3} } , where p = q × s

E(r) = \frac{kqs}{r^{3} } where r>>s

a) find the magnitude of force due to the dipole

F=QE

F= Q(\frac{kqs}{r^3})

where k = 1/4πε₀

F = Qqs/4πε₀r³

b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

τ = F sinθ × s

θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

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A charged particle moves through a magnetic field. In which situation is the magnetic force zero?
maksim [4K]

Answer:

The answer is the option a.

Explanation:

We know that magnetic force (Fm) is defined as

Fm = q (v x B)

Where q is a the value of the charge, v is the velocity of the charge and B is the value of the magnetic field.

"v x B" is defined as the cross product between the vectors velocity and magnetic field, and if the angle between them is thetha < 180°, then, the cross product is

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So,

Fm = qvBsin (thetha)

And, in case in which v and B are parallel vectors, thetha is zero, and,

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