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anyanavicka [17]
3 years ago
11

In Brownsville Texas it is 80°F the temperature is expected to drop 1.5° each hour in Mesquite Texas is 94°F and the temperature

is expected to drop 2° each hour how many hours for the temperature in Mesquite be greater than the temperature in Brownsville
Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

28 hours

Step-by-step explanation:

let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.

Given,

In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.

Now, according to the question,

after 'x' hours,

⇒ 80° - 1.5°(x) = 94° - 2°(x)

⇒ 0.5°(x) = 14°

⇒ x = 28

Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.

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compound interest equation for annually compounded

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t=time in years


given that

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find t


1550=1000(1+0.055)^t

divide both sides by 1000

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use ln rule ln(a^b)=b(ln(a))

ln(1.55)=t(ln(1.055))

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Answer:

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Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

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