no this relation is not a function, because for each input (x), there is no output (y)
Question 9.)
5-2(5)-1
10-1
Y=9
(X,Y) = 5,9
2- 2(2)-1
4-1
Y=3
(X,Y)= 2,3
0- 2(0)-1
2-1
Y=1
(X,Y)= 0,1
10)
4- 3(4)-7
12-7
Y=5
(X,Y)=4,3
1- 3(1)-7
3-7
Y=-4
(X,Y)= 1,-4
0- 3(0)-7
0-7
Y=-7
(X,Y)= 0,-7
(I believe you are supposed to plot the (X,Y) points on the graph)
Again, just simple addition and subtraction: $1,034.52
Answer:
Step-by-step explanation:
<em>Time</em><em> </em>is the dependent variable, so you set your function equal to <em>s</em>. Then, the correlation of the graph has a 
<em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] from the y-intercept of ![\displaystyle [0, 20],](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B0%2C%2020%5D%2C)
so we choose this answer choice.
I am joyous to assist you anytime.
