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zhenek [66]
3 years ago
12

Helps me solve this problem please

Mathematics
1 answer:
Kitty [74]3 years ago
5 0

Answer:

D. An infinite number of solutions

Step-by-step explanation:

The reason is because it doesn't equal anything.

2(x-5)=4x-2x-10

2x -10= 2x-10 ( You add the -2 plus the 4)

-2x        -2x

0x -10= 0 -10

     +10     +10

0x = 0

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The function f(x)=Acosh(Cx)+Bsinh(Cx). I need help determining the value of constant C&gt;0 when the second derivative f''(x)=25
Rus_ich [418]

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Step-by-step explanation:

First, you need to remember that:

For the function:

h(x) = Sinh(k*x)

We have:

h'(x) = k*Cosh(k*x)

and for the Cosh function:

g(x) = Cosh(k*x)

g'(x) = k*Cosh(k*x).

Now let's go to our problem:

We have f(x) = A*cosh(C*x) + B*Sinh(C*x)

We want to find the value of C such that:

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C = 5

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