Let the total no. of 25 p coins be x
50p coins = 2x
Value of 25 p coins ( in rupees) = 0.25*x =0.25x
Value of 50p coins ( in rupees) = 0.5*2x = x
0.25x+x = 25
1.25x =25
x = 25/1.25 = 20
no. if 25p coins = 20
and 50p coins = 2*20 = 40
According to the information given in the exercise, the following expression represents the area of the rectangular garden:

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.
Knowing the above, you can set up the following equation:

Where "A" is the area of the walkway around the rectangular garden.
Solving for "A", you get the following expression:

The answer is:
Answer:
let
hypotenuse[h]=60ft
base[b]=36ft
perpendicular [p]=48ft
by using Pythagoras law
p²+b²=h²
48²+36²=60²
2896≠3600
since p²+b²≠ h²[<u>so</u><u> </u><u>the</u><u> </u><u>stage</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>in</u><u> </u><u>a</u><u> </u><u>right</u><u> </u><u>angled</u><u> </u><u>tria</u><u>ngle</u><u>]</u><u>but</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>scalene</u><u> </u><u>triangle</u>
Answer:
Fourth root of 256 is ±4.
hope this helps