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maxonik [38]
3 years ago
10

1.5.PS-21

Mathematics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

Increase in the length of one side = 3.8 ft

Step-by-step explanation:

Yossi has garage whose area is 280 ft²

After rebuilt their is increment in area by 50%

New Area = 280 × 150% = 420 ft²

Also we know that Area of Square = (Length) × (Length)

⇒ Length of Newly built garage = √420 = 20.5 ft

and Length of Originally garage = √280 = 16.7 ft

⇒ Increase in the length of one side = 20.5 - 16.7 = 3.8 ft

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What is the value of x?<br> x = [ ? ]
Mnenie [13.5K]

Answer:

Step-by-step explanation:

The tangent to the angle makes an angle of 90° with the radius.

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Please I need help ASAP<br>pls explain your answer ​
USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

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Elena L [17]
5:4 Should be correct! I took the test Btw Hope this helps!! :D

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